3 years ago

How to solve this problem for my pre calculous class.

1 answer:

Vilka [71]3 years ago

4 0

Take the cos-1 of both sides to get 3x=30 then divide by 3 to get ×=10

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artcher [175]

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The third option.

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marta [7]

Answer:

A. -6

Step-by-step explanation:

$f(x)=3x-1\\\\$

In order to find $f(-2)$ we will plugin $x=-2$

$f(-2) = 3(-2)-1\\f(-2)=(3\times(-2))-1\\f(-2)=-6-1$

$f(-2)=-7$

$g(x)=-x+6$

In order to find $g(5)$ we will plugin $x=5$

$g(5)=-5+6$

$g(5)=1$

$f(-2)+g(5)\\=-7+1\\=-6$

∴ $f(-2)+g(5)=-6$

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Sunny_sXe [5.5K]

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Step-by-step explanation:

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