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uranmaximum [27]
3 years ago
5

What is the perimeter of a rectangle with a length of 7 3/4 inches and a width of 4 1/3 inches

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Multiply the length by 2, then multiply the width by 2 and then add them together.

7 3/4 x 2 = 15 1/2

4 1/3 x 2 = 8 2/3

15 1/2  = 31/2

8 2/3 = 26/3

Find common denominator:

31/2 x 3 = 93/6

26/3 x 2 = 52/6

93/6 + 52/6 = 145/6

145/6 = 24 1/6 inches.

MrMuchimi3 years ago
3 0

Answer:

24 1/6 or 145/6 inches

Step-by-step explanation:

( 7 3/4 inches x 2) + (4 1/3 inches x 2)= 145/6 which is 24 1/6

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<h2>Answer:</h2>

LP = 8 because LR + PR = LP according to the Segment Addition Postulate, and 8 + 4 = 12 using substitution

<h2>Step-by-step explanation:</h2>

From this problem, we know that:

LR = 12

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So here we have a Line segment. Recall that a line segment has two endpoints, places where they end or stop and they are named after their endpoints, so the line segment here is LR whose measure is 12. Then, according to Segment Addition Postulate it is true that:

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Subtracting 4 from both sides:

LP + 4 - 4 = 12 - 4

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Finally:

LP = 8

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