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Zina [86]
3 years ago
7

The difference of the square of a number and 5 is equal to 4 times that number. Find the negative solution.

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

x=-1 or x=5

Step-by-step explanation:

let the number be 'x'.

According to the statement given above:

x^2-5=4x

or

x^2-4x-5=0

Factorizing the quadratic equation for 'x'

x^2+x-5x-5=0

Taking common from the equation:

x(x+1)-5(x+1)=0\\(x+1)(x-5)=0\\(x+1)=0, (x-5)=0\\x=-1,x=5

The solution of the equation is x=-1 or x=5

ivann1987 [24]3 years ago
8 0

Answer:

its -1 because i know it

Step-by-step explanation:

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Which of the following statements are true about the graph? Check all that apply.
Alenkasestr [34]

Answer:

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Find the area of a regular octagon with an apothem of 7 inches and a side length of 5.8 inches. (nearest tenth)
Kisachek [45]

Answer:

162.4 in²

Step-by-step explanation:

LETS GET INTOOOOEEETTT

Let's start with what we know:

Area of regular octagon = 1/2 x perimeter x apothem

We know the apothem, so all that we need to find to fill in the above equation is the perimeter:

perimeter = 8 x 5.8 = 46.4in

Now we can fill in our original equation and solve:

Area of regular octagon = 1/2 x perimeter x apothem

Formula = n (s/2)² divided by tan( π /n)

   = 8 (5.8/2)²  divided by tan ( π /8)

                 = 162.4283 in²

ORRR when rounded to the nearest tenth,

                      =162.4 in²

6 0
3 years ago
Cual es tu sensibilidad para dar headshot en free fire?
Sav [38]

Answer:

General: 100.

Punto rojo: 75.

Alcance 2X: 69.

Alcance 4X: 62.

Alcance AWM: 34.

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El arma Groza es una buena arma para usar en situaciones de combate de mediano a largo alcance en Garena Free Fire.

El AWM es posiblemente el rifle de francotirador más fuerte de Garena Free Fire.

Step-by-step explanation:

depende del alcance que haya equipado

5 0
3 years ago
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iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

d=\sqrt{h^2+k^2}

Distance of P from ( -3, 4 ) :

d=\sqrt{(h+3)^2+(k-4)^2}

Now , these distance are equal :

h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2

Solving above equation , we get :

P=(\dfrac{16}{21},\dfrac{23}{7})

Hence , this is the required solution.

6 0
3 years ago
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