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3 years ago

I need help with algebra 2 pleasee

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

$x=\pm \sqrt{21}/7$

Step-by-step explanation:

We can add 9 to both sides of the equation to get $21x^2=9$ .

We can divide both sides of the equation by 21 to get $x^2=9/21$ .

We take the square root of both sides of the equation to get $x=\pm \sqrt{9/21}$ .

However, that isn't in the form we need.

We know that $\sqrt{9/21}=\sqrt{9}/\sqrt{21}=3/\sqrt{21}=3\sqrt{21}/(\sqrt{21}*\sqrt{21})=3\sqrt{21}/21=\sqrt{21}/7$

so the answer is really $x=\pm \sqrt{21}/7$ and we're done!

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Step-by-step explanation:

x = number of multiple choice questions

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--------------------

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3 years ago

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Answer:

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Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

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Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

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(c)

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Natalka [10]

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