Ok, so it seems
erm
ok, even and odd
it is an odd one because the power is odd (3rd degree)
so then the ends go in different directions
and since leading coefient (5 in the 5x^3) is positive, it goes from bottom left to top right
so
A is false
B is false
C and D are true
answer is C and D
Taxi A
1mile £3.50+£1.75=£5.25
Taxi B
1mile £1.25+£2.00=£3.25
Taxi A
2miles £3.50+£3.50=£7.00
Taxi B
2miles £1.25+£4.00=£5.25
Taxi A
3miles £3.50+£5.25=£8.75
Taxi B
3miles £1.25+£6.00=£7.25
Taxi A
4miles £3.50+£7.00=£10.50
Taxi B
4miles £1.25+£8.00=£9.25
Taxi A
5miles £3.50+£8.75=£12.25
Taxi B
5miles £1.25+£10.00=£11.25
Taxi A
6miles £3.50+£10.50=£14.00
Taxi B
6miles £1.25+£12.00=£13.25
Taxi A
7miles £3.50+£12.25=£15.75
Taxi B
7miles £1.25+£14.00=£15.25
Taxi A
8miles £3.50+£14.00=£17.50
Taxi B
8miles £1.25+£16.00=£17.25
Taxi A
9miles £3.50+£15.75=£19.25 (the same)
Taxi B
9miles £1.25+£18.00=£19.25 (the same)
^^^
They would have to drive 9 miles for the taxi to cost the same.
Hope this helped, this is the longest way to work it out but also the simplest.
It rained 1 and 4/10 centimeters. You have to first figure out what adds up to 14, which is 1/10. Then you add 1 to get 15 and 3/10 to get 15 3/10.
Answer:
Step-by-step explanation:
Given
Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:
Since 9 falls in category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)
