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2 years ago

Hich graph best represents a solution to the following system-2x-3y<9-x+y≤2

Mathematics

2 answers:

Pepsi [2]2 years ago

8 0

Answer:

Step-by-step explanation:

Dovator [93]2 years ago

4 0

Answer:

Answer C.

Step-by-step explanation:

When ran through Desmos (a really awesome tool), this is what I get :)

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Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply

kykrilka [37]

$\cos(2x) = \cos(x)$

Solution (1)

$2x = x + 2k\pi$

$2x - x = 2k\pi$

$x = 2k\pi$

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

$2x = - x + 2k\pi$

$2x + x = 2k\pi$

$3x = 2k\pi$

$x = \frac{2k\pi}{3}$

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

6 0

2 years ago

Sonia had $37 in her checking account. She then spent $52 on school supplies. What is the current balance of her checking accoun

stiv31 [10]

Answer:

-15

Step-by-step explanation:

37-52

4 0

3 years ago

Read 2 more answers

Conjectures and Postulates are accepted as true without formally proving they are true.

zlopas [31]

The answer is false, it is only true for postulates, not conjectures.

7 0

2 years ago

Read 2 more answers

Graph and write the solution:<br><br> Y= x - 4<br> Y= 1/3x - 2

Reika [66]

Answer:

1. x=4

2. x=6

Step-by-step explanation:

I've attached the graphs here:

Clearly, the solution for first one is(Reminder: the solution is the x-intercepts, when y is zero):

x=4

And the second is:

x=6

Hope this helps!

Mark brainliest if you think I helped! Would really appreciate!

6 0

2 years ago

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that $P(A \cup B) = 0.95$

80% passed in mathematics 75% passed in english

This means that $P(A) = 0.8, P(B) = 0.75$

Proportion who passed in both:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Considering the values we have for this problem

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6$

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

$0.6t = 3000$

$t = \frac{3000}{0.6}$

$t = 5000$

5000 students appeared in the examination.

4 0

2 years ago