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3 years ago

Hich graph best represents a solution to the following system-2x-3y<9-x+y≤2

Mathematics

2 answers:

Pepsi [2]3 years ago

8 0

Answer:

Step-by-step explanation:

Dovator [93]3 years ago

4 0

Answer:

Answer C.

Step-by-step explanation:

When ran through Desmos (a really awesome tool), this is what I get :)

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NO LINKS!!!<br><br>Find the indicated side for each triangle below:

pogonyaev

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

s/sin(78) = 10/sin(48)

s = sin(78)*10/sin(48)

s = 13.162274

<h3>Answer: 13.162274 approximately</h3>

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Problem 6

Use the Law of Sines here as well.

x/sin(X) = y/sin(Y)

x/sin(53) = 6/sin(22)

x = sin(53)*6/sin(22)

x = 12.791588

<h3>Answer: 12.791588 approximately</h3>

8 0

2 years ago

Read 2 more answers

Can someone please answer. There is one problem. There's a picture. Thank you!

Mnenie [13.5K]

Use the Sine Law: $\frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}$

In this case:
$\frac{sin(44)}{17}=\frac{sin(60)}{e}$
therefore:
$e=17\frac{sin(60)}{sin(44)} \approx 21.2$

6 0

3 years ago

HELP ME PLZZZZZZZZ ASAP

Alex_Xolod [135]

Answer:

find the common factor

Step-by-step explanation:

1)13

2) 13(1+5)

8 0

2 years ago

Read 2 more answers

PQRS is a parallelogram and T is the mid point of PQ if ar PTRS=24 cm^2, find the area of PQR

Lady_Fox [76]

Answer:

24 sq cm

Step-by-step explanation:

According to theorem of area if parallelogram and triangle, if the triangle and a parallelogram lie between two parallel line and their base is same then, the area of triangle is half of the area of the parallelogram. so here the parallelogram PTRS and the triangle PTR lie between same parallel lines PT and RS and base is also same PT. so area of PTR is 12sq cm. Again, triangles PTR and TRQ lie between same parallel lines PQ and SR and same base PQ. so their area also same that is 12 sq cm. Now, area of PQR = area of PTR + area of TRQ = 12 + 12 sq cm = 24 sq cm.

5 0

4 years ago

A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t

vladimir1956 [14]

Answer: 434.35 feet

Step-by-step explanation:

The angle of depression from the lighthouse is the angle of elevation from the boat. The line of sight from the top of the lighthouse, when depressed, becomes an alternate interior angle of two parallel lines, the line of sight from the top and the boat's movement.

From the boat's standpoint, which is what we want anyway, there is a right triangle, with the distance from the lighthouse the adjacent side, the opposite is 200,' and the boat the point desired.

tan 18.33 (33 minutes is 33/60 of a degree)=200/x

x=200/tan 18.33=592.58 feet

Nearer, the angle of elevation increases as the adjacent side gets smaller relative to the opposite side.

tan 51.33 (33 minutes is 33/60 of a degree)=200/x

x=200/tan 51.33=158.23 feet

That difference is 434.35 feet

Alternatively:

tan(51 33')= 200/base1

base1= 158.802

tan(18 33')=200/base2

base2=596.008

The distance travelled=596.008-158.802 =438m

5 0

4 years ago