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3 years ago

Identify the segment bisector of XY

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

The midpoint (W) of XY is also on segment PQ, so PQ is the bisector of XY.

Hope it helps you :)

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Pi/24 is the solution for 4cos2 (4x) - 3 = 0<br><br> True or false

inessss [21]

Answer:

True.

Step-by-step explanation:

Given,

4cos2 (4x) - 3 = 0

Now, 4π/24 = π/6

Or, cos π/6 = √3/2

Or, cos^2 π/6 = 3/4

Or, 4 cos^2 π/6 = 3

Now, Left Hand Side= 4cos2 (4x) - 3

= 3-3 =0 = Right Hand Side (Proved)

Here, Left Hand Side= Right Hanad Side. So, 4cos2 (4x) - 3=0 is true.

5 0

3 years ago

Read 2 more answers

Find a difference 118.419 - 6.74

nevsk [136]

Step-by-step explanation:

The difference between 118.419 and 6.74 is

= 111.679

Hope it helps

7 0

3 years ago

Plz plz plz help me out!!

slava [35]

Henry swims at 1.6 laps per minute, Larry swims at 1.8 laps per minute. Larry swims faster

6 0

3 years ago

Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).

ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

$\overrightarrow {PQ}==$

$\overrightarrow {PR}==$

The nonzero vector orthogonal to the plane through the points P,Q, and R is

$\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}$

$\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}$

Expand along row 1.

$\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}$

$\overrightarrow n=i(-9)-j(8)+k(2)$

$\overrightarrow n=-9i-8j+2k$

$\overrightarrow n=$

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0

3 years ago

Divide. −4 1/3 ÷ −2 3/5 A. 1 2/3 B. 1 4/5 C. 2 1/5 D. 2 3/5

Inga [223]

a. $1 \frac{2}{3}$

trust me it's the correct answer :)

7 0

3 years ago