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Sophie [7]
3 years ago
6

5x + 2y, when x = 5 and y = -2

Mathematics
1 answer:
den301095 [7]3 years ago
8 0

Answer:

21

Step-by-step explanation:

1. Simplify 5 × 5 to 25.

25 + 2 × -2

2. Simplify 2× −2  to −4.

25 − 4

3. Simplify.

21

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Help me pleaseeee :) for brainliest answer
kifflom [539]

Answer:

2:14, 1:7, 3:21, and 18:126

Step-by-step explanation:

They are all multiplying by 7.

2*7= 14

1*7= 7

3*7= 21

18*7= 126

Hope this helps! :)

8 0
3 years ago
A boy has in his pocket a 50-cent piece, two dimes and two pennies. If he pulls out a coin at random, what is the probability it
rodikova [14]
Well, from what I can tell he has 1 50 cent piece, 2 Dimes, and 2 Pennies. Meaning 5 objects in total, considering that it asks for "at least ten cents" that would mean the 2 Dimes and the 1 50 cent piece.
Since that is 3 objects out of the 5, being 3/5ths, that would mean he has a 60% chance or probability for the first draw.

Hopefully that helps. ^ ^
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3 years ago
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GalinKa [24]
The 2 fractions are the possibilities
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3 years ago
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Find the common ratio and the seventh term of the following sequence:<br> ş, ğ, 2, 6, 18, ...
Karolina [17]
54 is the one after 18
4 0
3 years ago
Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit
natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

Let  

a,b,c be the lengths of the sides of a triangle.  

The area is given by:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

p is half the perimeter

p=\frac{a+b+c}{2}

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}

d=\sqrt{(-4)^{2}+(0)^{2}}

dAB=4\ units

step 2

Find the distance BC

d=\sqrt{(-2+3)^{2}+(1+2)^{2}}

d=\sqrt{(1)^{2}+(3)^{2}}

dBC=\sqrt{10}\ units

step 3

Find the distance AC

d=\sqrt{(-2-1)^{2}+(1+2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

dBC=\sqrt{18}\ units

step 4

a=AB=4\ units

b=BC=\sqrt{10}\ units

c=AC=\sqrt{18}\ units

Find the half perimeter p

p=\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units

Find the area

A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}

A=\sqrt{5.7(1.7)(2.54)(1.46)}

A=\sqrt{35.93}

A=6\ units^{2}

7 0
3 years ago
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