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damaskus [11]
3 years ago
6

(1) Calculate the circumference of thecircles below in terms of π​

Mathematics
2 answers:
blagie [28]3 years ago
7 0

Answer:

A.

2 x 2 = 4 so 4 is the diameter because the diameter is double the radius

diameter x pi = circumference

4 x pi = 3pi or 12.56

8 x pi = 8pi or 25.12

Step-by-step explanation:

Mademuasel [1]3 years ago
3 0

Answer:12.57

Step-by-step explanation:

C=2πr

   =2·π·2

   =12.56637

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3 years ago
5. A fruit concentrate is sold in 250 mL packs. The instructions are 'Add water to make one litre of ready-to-drink fruit juice'
Ierofanga [76]
Given ,

Concentrate= 250 mL

Water = 1 liter = 1000 mL

A) ratio is 250:1000 = 1:4

B) for 250 mL it is 1 liter now for 2000mL it is X .

=> x = 2000/250 = 8 liters

C) volume of water in 6L of made up juice is 1500 mL

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4 0
2 years ago
Is 4.55 and 1.23456 a rational number
kaheart [24]

Problem

Is 4.55 and 1.23456 a rational number

Solution

4.55 can be written as:

455/100 so then it could be a rational number

For the second number we have: 1.23456

And we can write this number as:

123456/100000

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7 0
1 year ago
Name three decimals between 0.55 and 0.56
marshall27 [118]
Some decimals between 0.55 and 0.56 are 0.551, 0.552, 0.553, 0.554, 0.556, 0.557, 0.558, 0.559. 

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5 0
3 years ago
A,B and C are the vertices of one triangle.
dsp73

Answer:


Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is \frac{AD}{DB}=\frac{AE}{EC}, then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates=(\frac{4+2}{2},\frac{6-2}{2})=(3,2) and Mid Point E has coordinates=(\frac{4-2}{2},\frac{6-4}{2})=(1,1)

Now, AD= \sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}

DB=\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}

AE=\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}

EC=\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}

Now, \frac{AD}{DB}=\frac{AE}{EC}

=\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}

Hence, \frac{AD}{DB}=\frac{AE}{EC}

Thus, By basic proportionality theorem, DE is parallel to BC.

4 0
3 years ago
Read 2 more answers
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