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Eddi Din [679]
2 years ago
9

SOMEONE PLEASE I NEED HELL AND I WANT TO GO TO SLEEP, but there’s more than one answer btw

Mathematics
2 answers:
max2010maxim [7]2 years ago
7 0

Answer:

\frac{7^{18}}{7^{9}}, (7³)³ and 7^{4}*7^{5}

Step-by-step explanation:

7^{8}*7  = 7^{9} is equivalent to the following exponential expressions:

\frac{7^{18}}{7^{9}}, as it applies to the Quotient Rule of Exponents: \frac{a^{m}}{a^{n}} = a^{m-n}. Therefore, you're essentially subtracting the exponents, resulting into 7^{9}.

(7³)³: The Power-to-Power Rule of Exponents apply in this situation:(a^{m})^{n} = a^{mn}. Multiplying the exponent inside the parenthesis by the exponent outside the parenthesis results in an exponent of 9.

7^{4}*7^{5}: the Product Rule of Exponents apply in this situation: a^{m}*a^{n} = a^{m+n}. Adding the exponents of 4 to 5 results in an exponent of 9.  

Please mark my answers as the Brainliest, if you find this helpful :)

ira [324]2 years ago
3 0

Answer:

The second one, third one and the fifth one should be correct. (7 to the 18th power divided 7 to the 9th power, 7 to the 3rd power to the 3rd power, and 7 to the 4th power times 7 to the 5th power)

Step-by-step explanation:

7 to the 8th power times 7 equal 40353607 so if you do all the equations shown you can rule out which ones equal 40353607 and which ones don't. Have a nice sleep!

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0.2.0.4, 0.6, 0.8, 1....<br> Arithmetic or geometric
Basile [38]

Arithmetic sequences have a common difference between consecutive terms.

Geometric sequences have a common ratio between consecutive terms.

Let's compute the differences and ratios between consecutive terms:

Differences:

0.4-0.2 = 0.2,\quad 0.6-0.4=0.2,\quad 0.8-0.6=0.2,\quad 1-0.8=0.2

Ratios:

\dfrac{0.4}{0.2}=2,\quad \dfrac{0.6}{0.4} = 1.5,\quad \dfrac{0.8}{0.6} = 1.33\ldots, \quad\dfrac{1}{0.8}=1.25

So, as you can see, the differences between consecutive terms are constant, whereas ratios vary.

So, this is an arithmetic sequence.

3 0
2 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
Help on this to please
d1i1m1o1n [39]

Answer:

7). up 4 over  4

8). up 1 over 2

Step-by-step explanation:

hope this helps :)

5 0
2 years ago
Read 2 more answers
Use the expression 5a – 2b – 3 + 2b – 6a.
ella [17]

Answer:

5a + (-6a) + (-2b) + 2b + (-3) = -a -3 or -(a + 3) so first answer is correct because -(a + 3) is the same as -(3 + a)

Step-by-step explanation:

4 0
2 years ago
Hello pls help besties (o˘◡˘o)
goldenfox [79]
Hello bestie I cannot help you
8 0
2 years ago
Read 2 more answers
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