Question

What is an equation of the line that passes through the point (5,-2)(5,−2) and is parallel to the line 2x-5y=352x−5y=35?

Answer 1

Answer:

2x-5y=20.

Step-by-step explanation:

1) according to the condition the required line is parallel to the given line, it means, that the equation of the required line is:

2x-5y=C, where C - unknown number;

2) in order to calculate unknown 'C' it needed to substitute the given coordinates into the equation of the required line, then:

2*5-5*(-2)=C; ⇒ C=20.

3) the required equation of the line is:

2x-5y=20.