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ICE Princess25 [194]
2 years ago
5

Can someone check my answers and tell me if it’s right or not? Thank you so much :)

Mathematics
2 answers:
Tpy6a [65]2 years ago
8 0

Answer:

some are correct but some are not.

Step-by-step explanation:

You got to pay attention to all the negatives in the equations. Number 3 is incorrect. The reason is  you started the plot at positive 6 not negative 6

inessss [21]2 years ago
3 0

Answer:

yes i think u are correct

Step-by-step explanation:

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137x8 multiply with expanded form please help 10 ponte for your help please help!
Step2247 [10]

Answer: maybe 20

Step-by-step explanation:

or find it out yourself

3 0
2 years ago
Mason gave the waiter a $14.58 tip, which was 15 percent of the dinner bill. What was the amount of the dinner bill before he ad
Svetlanka [38]

Answer:

C. You take the tip amount devided by 15%. Thats 0.15. You the get the answer 97.20

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the equation of the line that passes through the points (-1, 3) and (1, 11)
lina2011 [118]

Answer: To find the slope of this line, you would use the fomula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

4

The slope of your line would be 4

3 0
3 years ago
Can you find the marginal profit of a,b and c?
MakcuM [25]
Keeping in mind that for a cost C(x) and profit P(x) and revenue R(x), the marginal cost, marginal profit and marginal revenue are respectively dC/dx, dP/dx and dR/dx, then

\bf P(x)=0.03x^2-3x+3x^{0.8}-4400
\\\\\\
\stackrel{marginal~profit}{\cfrac{dP}{dx}}=0.06x-3+2.4x^{-0.2}
\\\\\\
\cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{0.2}}\implies \cfrac{dP}{dx}=0.06x-3+2.4\cdot \cfrac{1}{x^{\frac{1}{5}}}
\\\\\\
\cfrac{dP}{dx}=0.06x-3+\cfrac{2.4}{\sqrt[5]{x}}

\bf a)\qquad 
\cfrac{dP}{dx}=0.06(200)-3+ \cfrac{2.4}{\sqrt[5]{200}}
\\\\\\
b)\qquad \cfrac{dP}{dx}=0.06(2000)-3+\cfrac{2.4}{\sqrt[5]{2000}}
\\\\\\
c)\qquad \cfrac{dP}{dx}=0.06(5000)-3+\cfrac{2.4}{\sqrt[5]{5000}}
\\\\\\
d)\qquad \cfrac{dP}{dx}=0.06(10000)-3+\cfrac{2.4}{\sqrt[5]{10000}}
3 0
2 years ago
Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.
Dafna1 [17]

Answer:

\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

Step-by-step explanation:

When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

The figure EFG and its reflection E'F'G' are shown in the diagram below.

6 0
3 years ago
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