The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)
Thus we have two foci
(0,3) and (0,-3)
Answer:
<h2><u>
104.9</u></h2>
Step-by-step explanation:
To find the circumference of a circle, we need to use the formula which is
C = 2*π*r
Rewrite with radius
C = 2*π*16.7
Solve
C = 2*π*16.7 = 104.876
Now we have to round. Remember, if it is 4 or below round down and if it is 5 or above, round up.
104.876 - 6 is more than 5
104.88 - 8 is more than 5
<u>104.9 is the final answer</u>
You first must find the constant of variation, k. Then substitute it back in to the direct variation form.
Answer:
Step-by-step explanation:
3(a^2 + a - 6)
3(a + 3)(a - 2)
answer is D