Question

F(x)=2x^2-3x find f(7) (Also can someone help me with the other 2?)

Answer 1

Answer:

$f(x) = 2 {x}^{2} - 3x \\ f(7) = 2( {7}^{2} ) - 3(7) \\ = 2(49) - 21 \\ = 98 - 21 \\ = 77 \\ g(x) = 4 {x}^{2} + 9x \\ g(3x) = 4(3 {x}^{2} ) + 9(3x) \\ = 4(9 {x}^{2} ) + 27x \\ = 36 {x}^{2} + 27 {x}^{2} \\ = 9x(4x + 3) \\ f(n) = 3 {n}^{2} - 5n + 2 \\ f( - 3) = 3( - {3}^{2} ) - 5( - 3) + 2 \\ = 3(9) + 15 + 2 \\ = 27 + 15 + 2 \\ = 44$

Step-by-step explanation:

Hope that this is helpful.

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