Question

Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16

Answer 1

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

Given:

$2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)$

Use the Power Rule Law:

$log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)$

Use the Quotient Rule Law:

$log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})$

Use the Product Rule Law:

$log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})$

Simplify:

$log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})$

$\frac{4}{9}=\frac{8\sqrt{x}}{9}$

$4=8\sqrt{x}$

$\frac{4}{8}=\sqrt{x}$

$\frac{1}{2}=\sqrt{x}$

$\frac{1}{4}=x$