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3 years ago

Tính giá trị biểu thức 18(-xy)^4 : (4x^2y)^2

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

5 0

Answer:

Tdjdjfhbs djdjdjdjd djdjdjjdjd

Step-by-step explanation:

Brainiest ududhdhxhc

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Fifty balls are numbered 1 to 50 and a red dot is painted on those balls that are a multiple of 6. The balls are mixed into a ba

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Step-by-step explanation:

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3 years ago

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3 years ago

Put the following equation of a line into slope-intercept form, simplifying all

soldier1979 [14.2K]

Answer: y = 2x - 2

Explanation: The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Subtract 2x from both sides of the equation.
-y = 2 - 2x
Multiply each term in -y = 2 - 2x by -1
(-y) . -1 = 2 . -1 + (-2x) . -1
Multiply (-y) . -1
Multiply -1 by -1
Multiply y by 1
y = 2 . -1 + (-2x) . -1
Simplify each term
Multiply 2 by -1
y = -2 + (-2x) . -1
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4 0

3 years ago

4√16/625 Can someone tell me how to solve this because i am really confused

geniusboy [140]

First find the root of 16 which is =4 then times 4*4 =16 then divide by 625 . so 4*4/625 is .0256 is the answer

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3 years ago

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

4 0

4 years ago