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2 years ago

Emma strikes a match and sets some logs on fire. As the fire burns, which two forms of energy are released?

Chemistry

1 answer:

Ivanshal [37]2 years ago

7 0

Answer:

Explanation:

There are changes in the chemical composition of the word.

There's light energy given off.

There's heat energy given up.

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What is the pH of a solution with a H+ ion of 2×10-¹²?

kap26 [50]

Answer:

11.7

Explanation:

The pH is the negative logarithm of the concentration of H+ ions. If the concentration is 2×10-¹² the the pH will be -log(2×10-¹²) which is 11.698 which can be round up to 11.7.

5 0

3 years ago

2MG+O2 ...........2MGO

Galina-37 [17]

Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced

5 0

2 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

Have a nice day!

8 0

3 years ago

For the chemical reaction

polet [3.4K]

Answer:

806.3g

Explanation:

Given parameters:

Number of moles of silver nitrate = 4.85mol

Unknown:

Mass of silver chromate = ?

Solution:

2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃

To solve this problem, we work from the known to the unknown;

The known specie here is AgNO₃ ;

From the balanced chemical equation;

2 moles of AgNO₃ will produce 1 mole of Ag₂CrO₄

4.85 moles of AgNO₃ will produce $\frac{4.85}{2}$ = 2.43moles of Ag₂CrO₄

Mass of silver chromate produced;

mass = number of moles x molar mass

Molar mass of Ag₂CrO₄

Atomic mass of Ag = 107.9g/mol

Cr = 52g/mol

O = 16g/mol

Input the parameters and solve;

Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol

So,

Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g

8 0

2 years ago

There are two different compounds of sulfur and fluorine.

Sedaia [141]

<span>1.18 x 3 = 3.55 </span>
find ratio of F to F in each compound
. according to law of multiple proportions that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers.
now F is "one element" and S has "fixed mass",
the ratio of F6 to Fx = 3:1
<span>thats why x= 2
there is less F in SFx
the ratio is 3:1.
dividing 6 by 3 and you get 2</span>

5 0

3 years ago