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LuckyWell [14K]
2 years ago
9

Emma strikes a match and sets some logs on fire. As the fire burns, which two forms of energy are released?

Chemistry
1 answer:
Ivanshal [37]2 years ago
7 0

Answer:

Explanation:

There are changes in the chemical composition of the word.

There's light energy given off.

There's heat energy given up.

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What are the correct coefficients for each reactant and product when this equation is balanced? Make sure to select the correct
Mars2501 [29]

Answer: 44

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3 years ago
What portion of your salt solution in ice water system is: a. A mixture? b. A solution?
ahrayia [7]

The salt and water are a homogeneous mixture but when salt dissolves in the water system is called a solution of salt and water.

<h3>What is a mixture? </h3>

A mixture is defined as the combination of two or more substances that are not chemically bonded together.

There are two types of mixture which include:

  • Homogeneous (uniform composition) and

  • Heterogeneous mixtures

When salt is added to the ice water system, it lowers the freezing point of the ice water thereby forming a homogenous mixture of water and salt.

The dissolution of salt in ice water leads to the formation of salt and water solution.

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brainly.com/question/10677519

8 0
2 years ago
Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0
3 years ago
Two isotopes of hypothetical element X exist with abundances of 30.00% 100X and 70.00% 101X. What is the approximate atomic mass
Rasek [7]

Answer:

C. 100.7 amu

Explanation:

Isotopes of an element are atoms of an element with the same atomic number but different atomic masses. Each atomic mass of an isotope is known as an isotopic mass. An element that exhibits isotope, that is, that have two or more isotopes has a relative atomic mass that is not a whole number.

Relative atomic mass of X is the sum of the products of the relative abundances of each isotope and its isotopic mass.

For Isotope ¹⁰⁰X: 30% × 100 = 30 amu

For Isotope ¹⁰¹X: 70% × 101 = 70.7 amu

Relative atomic mass of X = (30 + 70.7) amu = 100.7 amu

Therefore, the approximate atomic mass of X is 100.7 amu

4 0
2 years ago
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