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Karolina [17]
3 years ago
8

Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?

Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK =  -  ΔG₀ / RT

K = e^{-\frac{\triangle G_0}{RT}

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K  .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .

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In order to gain one pound of body weight, the average person must consume 3500 more calories
Fed [463]

Answer:

<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.

Explanation:

We can use ratios to calculate the answer using the information given in the question.

1 pound : 3500 grams

5 pounds : x grams

As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.

<u><em>Method</em><em> </em><em>A</em><em>:</em></u>

To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.

x = 3500 × 5

x = 17500

<em><u>Method B</u>:</em>

To solve for the answer x, we can convert the ratios into fractions.

1 / 5 = 3500 / x

3500 / x = 1 / 5

To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.

x = 5 × 3500

x = 17500

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How many molecular orbitals would be present in a molecule with the formula: ch2o?
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