Question

Choose the best answer below. Which of the following reactions will have the largest equilibrium constant at 298 K?

Answer 1

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK =  -  ΔG₀ / RT

$K = e^{-\frac{\triangle G_0}{RT}$

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K  .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .