Answer:
In Science, the word "theory" refers to the way that we interpret facts.
<u>Answer:</u> The expression for equilibrium constant is ![K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D%5BCl_2%5D%5E2%7D)
<u>Explanation:</u>
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_{eq}](https://tex.z-dn.net/?f=K_%7Beq%7D)
For the general chemical equation:
![aA+bB\rightleftharpoons cC+dD](https://tex.z-dn.net/?f=aA%2BbB%5Crightleftharpoons%20cC%2BdD)
The expression for
is given as:
![K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
For the given chemical reaction:
![2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)](https://tex.z-dn.net/?f=2HgO%28s%29%2BH_2O%28l%29%2B2Cl_2%28g%29%5Crightleftharpoons%202HOCl%28aq.%29%2BHgO.HgCl_2%28s%29)
The expression for
is given as:
![K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHOCl%5D%5E2%5BHgO.HgCl_2%5D%7D%7B%5BHgO%5D%5E2%5BH_2O%5D%5BCl_2%5D%5E2%7D)
The concentration of solid is taken to be 0.
So, the expression for
is given as:
![K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D%5BCl_2%5D%5E2%7D)
Hey how are you! Your answer would be
B . As water temperature increases,solubility increases.
Answer:
![Na^+_{ions}=3.33x10^{23}Na^+_{ions}](https://tex.z-dn.net/?f=Na%5E%2B_%7Bions%7D%3D3.33x10%5E%7B23%7DNa%5E%2B_%7Bions%7D)
Explanation:
Hello,
In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:
![n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4](https://tex.z-dn.net/?f=n_%7BNa_2SO_4%7D%3D0.850%5Cfrac%7Bmol%7D%7BL%7D%2A0.325L%3D0.276molNa_2SO_4)
Now, by using the Avogadro's number, the ions result:
![Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}](https://tex.z-dn.net/?f=Na%5E%2B_%7Bions%7D%3D0.276molNa_2SO_4%2A%5Cfrac%7B2molNa%5E%2B%7D%7B1molNa_2SO_4%7D%20%2A%5Cfrac%7B6.022x10%5E%7B23%7DNa%5E%2B_%7Bions%7D%7D%7B1molNa%5E%2B%7D%20%5C%5C%5C%5CNa%5E%2B_%7Bions%7D%3D3.33x10%5E%7B23%7DNa%5E%2B_%7Bions%7D)
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