The statement is an equation which is written in text form or in words. when we write it as an equation it will be:
squares of w and x is equal to w² and x² so, their sum means they are going to add.
3 + (w² + x²) = 32
three plus the sum of w² and x² is 32.
when we describe or write quantity with an equal sign it makes an equation.
Answer:
58 dollars (0.20) + 58 dollars
Step-by-step explanation:
58 dollars (0.20) + 58 dollars
To calculate the relative vector of B we have to:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
The coordenates of:
, with respect to B satisfy:

Equating coefficients of like powers of t produces the system of equation:

After solving this system, we have to:

And the result is:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
Learn more: brainly.com/question/16850761
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
The answer should be A which is:
<span>
If the measure of an angle is 90, then it is a right angle.
Original: true
Converse: true
</span><span>p is angel is right
</span><span> q is its measure is 90
</span><span>the statement is p then q
so the converse is q then p </span>
Answer: Brielle will run the marathon faster.
Brielle = 104.8 minutes
Joshua = 157.2 minutes
Step-by-step explanation:
Speed rate = distance /time
Brielle = 1.25 /10 = 0.125 miles per minute
Joshua = 1.5/18 = 0.083333 =1/12 miles per minute
Since 0.125 (Brielle) > 1/12 (Joshua)
Brielle will run the marathon faster.
To calculate the time that takes each one to run the entire race (13.1 miles)
Time= distance / speed
- Brielle = 13.1 /0.125 = 104.8 minutes
- Joshua = 13.1 / (1/12)= 157.2 minutes
Feel free to ask for more if needed or if you did not understand something.