4(3m-8)=-80 solve each equation for the given variable

The volume of a triangular prism is 20 cubic mm. If the dimensions were doubled, what would the new

anygoal [31]

Answer:

The new volume will be 160 mm^3

Step-by-step explanation:

The volume of a triangular prism can be calculated by multiplying the area of the triangular base by the height.

Let’s say we have the base with dimensions a and b, while the height can be h

The volume can be calculated as

V = 1/2 * a * b * h

Now , to answer this question, we shall be choosing arbitrary lengths for a, b and h. Whatever length we shall be choosing , we should make sure that they must be equal to 20 mm^3.

Let’s say we have a as 2mm , b as 4 mm and H as 5 mm

Plugging these into the equation, we surely have our volume as 20 mm^3

Now let’s double these dimensions. Our new dimensions become , 4mm by 8mm by 10mm

Plugging these new values into the equation, we have;

1/2 * 4 * 8 * 10 = 160 mm^3

Thus, our volume is expected to be increased by a factor of 8

7 0

3 years ago

HELP URGENT!!!!!!!!!!!!!!!!!!!!!!!!!

Ainat [17]

First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.

15×18=270
(9x12)+(4×5)=128
270-128=142

Area= 142ft^2

5 0

3 years ago

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Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we

Delvig [45]

Answer:

Step-by-step explanation:

Let's first find the exponential function that models the situation in year one. The exponential standard form is

$y=a(b)^x$ where a is the initial value and b is the growth/decay rate in decimal form. If it is growth it is added to 100% of the initial value; if it is decay it is taken away from 100% of the initial value. We are told that the number of cars in year one was 80 million, so

a = 80 (in millions)

If b is increasing by 10%, then we are adding that amount to the initial 100% we started with to give us 100% + 10% = 110% or, in decimal form, 1.1

The model for our situation is

$y=80(1.1)^x$ where y is the number of cars after x years goes by. We want to find the difference between years 3 and 2, so we will use our model twice, replacing x with both a 2 and then a 3 and subtracting.