I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
(a)
,
,
,
,
,
,
.
(b)
,
,
,
,
,
,
,
.
Step-by-step explanation:
In this exercise we only need to recall the formula for C(n,k):

where the symbol
is the factorial and means
.
By convention 0!=1. The most important property of the factorial is
, for example 3!=1*2*3=6.
(a) The explanations to the solutions is just the calculations.
.
(b) The explanations to the solutions is just the calculations.
For all the calculations just recall that 4! =24 and 5!=120.
Answer:
Step-by-step explanation:
Let x be the brother's weight.
Then 2x-5 is Andy's weight.
x+(2x-5)=100
3x-5=100
3x=105
Answer:
the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
Step-by-step explanation:
since the variance S² of the batch follows a normal distribution , then for a sample n of 20 distributions , then the random variable Z:
Z= S²*(n-1)/σ²
follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom
since
S² > 3.10 , σ²= 1.75 , n= 20
thus
Z > 33.65
then from χ² distribution tables:
P(Z > 33.65) = 0.02020
therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)
The number of participants with laptop is 115 and without laptop is 161
<u>Step-by-step explanation:</u>
Total number of participants= 276
Participants with laptop = (5/12) 276
= 115
Participants without laptop= 276 - 115
= 161