Not sure how to give a hint without blatantly giving the answer but...
Consider an n - digit number in base b.
That is N=an−1an−2.....a0=∑k=0akbk
N
=
a
n
−
1
a
n
−
2
.
.
.
.
.
a
0
=
∑
k
=
0
a
k
b
k
Note aka
k
<
b
so we can easily show NN
<
b
n
(may have to repeat and argue inductively.
And presumably to be n - digit than an−1≠0
a
n
−
1
≠
0
so N≥bn−1
N
≥
b
n
−
1
.
So we have: every n digit number is between bn−1
b
n
−
1
inclusively and bn
b
n
exclusively. This should be blindingly obvious to us if b=10
b
=
10
.
So... that's a really important and fundamental result. Remember and use it.
<h3>9)</h3><h3>5 planes</h3>
<h3>10)</h3><h3>2 planes</h3>
<h3>11)</h3><h3>BCED</h3>
<h3>12)</h3><h3>Yes , they belong to plane (w)</h3>
Answer:
x = 5
Step-by-step explanation:
x + 3 = 8
x = 8 - 3
x = 5
Answer:
Negative
Step-by-step explanation:
Assume that you mean if c÷d is positive or negative when c > 0 and d < 0
c > 0 means that c is positive
d < 0 means that d is negative
positive divides negative is always negative.
Thus, c÷d is negative when c > 0 and d < 0
