<u>Answer:</u> The number of molecules of carbon dioxide gas are 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,
= Henry's constant = 
= molar solubility of carbon dioxide gas
= pressure of carbon dioxide gas = 0.250 atm
Putting values in above equation, we get:

To calculate the number of moles for given molarity, we use the equation:

Molarity of carbon dioxide = 
Volume of solution = 0.550 L
Putting values in above equation, we get:

According to mole concept:
1 mole of a compound contains
number of molecules
So,
moles of carbon dioxide will contain =
number of molecules
Hence, the number of molecules of carbon dioxide gas are 
Answer : The [H] is increasing at the rate of 0.36 mol/L.s
Explanation :
The general rate of reaction is,

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.
The expression for rate of reaction will be :
![\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20A%7D%3D-%5Cfrac%7B1%7D%7Ba%7D%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D)
![\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20B%7D%3D-%5Cfrac%7B1%7D%7Bb%7D%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D)
![\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%20of%20C%7D%3D%2B%5Cfrac%7B1%7D%7Bc%7D%5Cfrac%7Bd%5BC%5D%7D%7Bdt%7D)
![\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%20of%20D%7D%3D%2B%5Cfrac%7B1%7D%7Bd%7D%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D)
![Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}](https://tex.z-dn.net/?f=Rate%3D-%5Cfrac%7B1%7D%7Ba%7D%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7Bb%7D%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D%3D%2B%5Cfrac%7B1%7D%7Bc%7D%5Cfrac%7Bd%5BC%5D%7D%7Bdt%7D%3D%2B%5Cfrac%7B1%7D%7Bd%7D%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D)
From this we conclude that,
In the rate of reaction, A and B are the reactants and C and D are the products.
a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.
The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.
The given rate of reaction is,

The expression for rate of reaction :
![\text{Rate of disappearance of }D=-\frac{1}{2}\frac{d[D]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DD%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D)
![\text{Rate of disappearance of }E=-\frac{1}{3}\frac{d[E]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DE%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BE%5D%7D%7Bdt%7D)
![\text{Rate of disappearance of }F=-\frac{d[F]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20disappearance%20of%20%7DF%3D-%5Cfrac%7Bd%5BF%5D%7D%7Bdt%7D)
![\text{Rate of formation of }G=+\frac{1}{2}\frac{d[G]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%20of%20%7DG%3D%2B%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BG%5D%7D%7Bdt%7D)
![\text{Rate of formation of }H=+\frac{d[H]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20formation%20of%20%7DH%3D%2B%5Cfrac%7Bd%5BH%5D%7D%7Bdt%7D)
![\text{Rate of reaction}=-\frac{1}{2}\frac{d[D]}{dt}=-\frac{1}{3}\frac{d[E]}{dt}=-\frac{d[F]}{dt}=+\frac{1}{2}\frac{d[G]}{dt}=+\frac{d[H]}{dt}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20of%20reaction%7D%3D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BE%5D%7D%7Bdt%7D%3D-%5Cfrac%7Bd%5BF%5D%7D%7Bdt%7D%3D%2B%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BG%5D%7D%7Bdt%7D%3D%2B%5Cfrac%7Bd%5BH%5D%7D%7Bdt%7D)
Given:
![-\frac{d[D]}{dt}=0.18mol/L.s](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D%3D0.18mol%2FL.s)
As,
![-\frac{1}{2}\frac{d[D]}{dt}=+\frac{d[H]}{dt}=0.18mol/L.s](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7Bd%5BD%5D%7D%7Bdt%7D%3D%2B%5Cfrac%7Bd%5BH%5D%7D%7Bdt%7D%3D0.18mol%2FL.s)
and,
![+\frac{d[H]}{dt}=2\times 0.18mol/L.s](https://tex.z-dn.net/?f=%2B%5Cfrac%7Bd%5BH%5D%7D%7Bdt%7D%3D2%5Ctimes%200.18mol%2FL.s)
![+\frac{d[H]}{dt}=0.36mol/L.s](https://tex.z-dn.net/?f=%2B%5Cfrac%7Bd%5BH%5D%7D%7Bdt%7D%3D0.36mol%2FL.s)
Thus, the [H] is increasing at the rate of 0.36 mol/L.s
Answer:
Many areas of the United States experience explosive population growth. <u>The more people that reside someplace, the more demand there is for water there.</u> Often these urban-growth <u>expansions are unplanned and place extraordinary stress on the water supply system, mainly on the groundwater.</u> <u>The stress often depletes groundwater supply, thereby causing wells to dry up.</u> Then water must be brought from somewhere else to support the local population.
Such situations have occurred all over the United States. For example, increased population growth in the southwestern United States has significantly lowered the water table 50 to 200 feet (depending on the area) since the 1940s. Managing urban growth, efforts to reduce water demand, conservation of the resource, and attempts to increase the water supply all address the problem of exceeding water resource limits.
<u>Human activities affect groundwater quality.</u>
<u>Here are some sources </u>and possible solutions to groundwater pollution:
<u>Agriculture</u>—Reduce usage of pesticides and fertilizers.
<u>Landfills</u>—Monitor for leakage and repair linings.
<u>Underground storage tanks</u>—Remove damaged and unused tanks.
<u>Household wastes</u>—Properly dispose of household hazardous waste.
<u>Septic tank leaks</u>—Properly maintain and repair tanks.
Explanation:
This came from the K12 learning course read this and the answer will be there. I underlined the important parts for the answer.
Answer:
The element is strontium and the number of neutrons it have is 51.
Explanation:
Based on the given information, the ionic compound is,
XCl₂ ⇔ X₂⁺ + 2Cl⁻
X2+ is the ion of the mentioned element
As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,
No. of electrons = atomic number - charge
36 = atomic number - 2
Atomic number = 38
Based on the periodic table, the atomic number 38 is for strontium element, and the sign of strontium is Sr. Hence, the element X is Sr.
Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,
No. of neutrons = mass number - atomic number
= 89 - 38
= 51 neutrons.
5.6L of O2 means we have 0.25 moles of O2.
As, 1 mole has 6.023*10^23 molecules,
0.25 moles of O2 will have 0.25*6.023*10^23 molecules=1.50575*10^23 molecules
and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.