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3 years ago

Why is stability of compounds essential

Chemistry

2 answers:

yuradex [85]3 years ago

7 0

Answer:

chemical stability is important to consider in the comprehensive assessment of pharmaceutical properties, activity, and selectivity during drug discovery.

Ray Of Light [21]3 years ago

5 0

Answer:

In general, molecules are stable because all their constituent atoms have sufficient "valence" electrons-that is, electrons that participate in chemical bonding. Such electrons reside in the outer, or valence, "shell," which must fill up with the appropriate number of electrons for the bound atoms to be come stable.

Explanation:

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A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h

NikAS [45]

Nitrogen combine with hydrogen to produce ammonia $\text{NH}_3$ at a $1:3:2$ ratio:

$\text{N}_2 \; (g) + 3 \; \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)$

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. $3 \; \text{mol}$ of hydrogen gas would have been consumed while $2 \; \text{mol}$ of ammonia would have been produced. The final mixture would therefore contain

$17 \; \text{mol}$ of $\text{H}_2 \; (g)$ and
$2 \; \text{mol}$ of $\text{NH}_3 \; (g)$

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

$\begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 1.926 \times 10^{3} \; \text{kPa} \end{array}$
$\begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 1.723 \times 10^{3} \; \text{kPa} \end{array}$
$\begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 2.037 \times 10^{2} \; \text{kPa} \end{array}$

6 0

3 years ago

Daniel has a sample of pure copper. Its mass is 89.6 grams (g), and its volume is 10 cubic centimeters (cm3). What’s the density

vlada-n [284]

Density = mass /volume = 89.6/10 = 8.96gm/cm^3.

8 0

3 years ago

A sample initially contains 8.0 moles of a radioactive isotope. How much of the sample remains after four half-lives? Express yo

Tju [1.3M]

Answer:

0.50 mol

Explanation:

The half-life is <em>the time required for the amount of a radioactive isotope to decay to half that amount</em>.

Initially, there are 8.0 moles.

After 1 half-life, there remain 1/2 × 8.0 mol = 4.0 mol.

After 2 half-lives, there remain 1/2 × 4.0 mol = 2.0 mol.

After 3 half-lives, there remain 1/2 × 2.0 mol = 1.0 mol.

After 4 half-lives, there remain 1/2 × 1.0 mol = 0.50 mol.

6 0

3 years ago

How do the muscular and skeletal systems work together to allow us to move?

BlackZzzverrR [31]

I would say it is B because when u pull ur leg up the space in your muscles are smaller when you spread your leg out they relax because they are not pulling anything.<span />

7 0

3 years ago

Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value.

ZanzabumX [31]

It has 5 digits so the exponent of 10 will be 4:-
61,103 =
6.1103 x 10^4

B

6 0

4 years ago

Read 2 more answers