Answer:
Oxygen supports combustion so a good method of testing for oxygen is to take a glowing splint and place it in a sample of gas, if it re-ignites the gas is oxygen. This is a simple but effective test for oxygen.
Explanation:
Answer:
The frequency of the photon is 7.41*10¹⁶ Hz
Explanation:
Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:
E = h*v
where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).
So the frequency will be:
Being E= 4.91*10⁻¹⁷ J and replacing:
You can get:
v= 7.41*10¹⁶ 
= 7.41*10¹⁶ Hz
<u><em>The frequency of the photon is 7.41*10¹⁶ Hz</em></u>
<u><em></em></u>
Answer:
37.98 kPa.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂)</em>
<em></em>
P₁ = 101.3 kPa, V₁ = 1.5 L,
P₂ = ??? kPa, V₂ = 4.0 L.
- Applying in the above equation
<em>(P₁V₁) = (P₂V₂)</em>
<em></em>
<em>∴ P₂ = (P₁V₁)/V₂</em> = (101.3 kPa)(1.5 L)/(4.0 L) = <em>37.98 kPa.</em>
