A flexible container at an initial volume of 8.15 l contains 6.51 mol of gas. more gas is then added to the container until it r
1 answer:
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Explanation:
will dissociate into ions as follows.
Hence, for this reaction will be as follows.
We take x as the molar solubility of when we dissolve x moles of solution per liter.
Hence, ionic molarities in the saturated solution will be as follows.
=
+ x
=
+ 2x
So, equilibrium solubility expression will be as follows.
=
Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains = 0.10 and there will be no lead ions. So,
= 0
So, will approximately equals to
.
Hence,
x = M
Thus, we can conclude that molar solubility of is
M.
Answer :
(a) The name for is titanium(IV) oxide.
(b) The name for is barium chloride.
(c) The name for is copper(III) chloride.
(d) The name for is potassium iodide.
(e) The name for is strontium chloride.
(f) The name for is copper(II) bromide.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(a)
is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for is titanium(IV) oxide.
(b)
is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for is barium chloride.
(c)
is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for is copper(III) chloride.
(d)
is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for is potassium iodide.
(e)
is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for is strontium chloride.
(f)
is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for is copper(II) bromide.