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aivan3 [116]
3 years ago
11

A flexible container at an initial volume of 8.15 l contains 6.51 mol of gas. more gas is then added to the container until it r

eaches a final volume of 12.7 l. assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
kirill [66]3 years ago
3 0
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
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Cu+2AgNO
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Answer:

Mass of Ag produced = 64.6 g

Note: the question is, how many grams of Ag is produced from 19.0 g of Cu and 125 g of AgNO3

Explanation:

Equation of the reaction:

Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2

From the equation above, 1 mole of Cu reacts with 2 moles of AgNO3 to produce 2 moles of Ag and 1 mole of Cu(NO3)2.

Molar mass of the reactants and products are; Cu = 63.5 g/mol, Ag = 108 g/mol, AgNO3 = 170 g/mol, Cu(NO3)2 = 187.5 g/mol

To determine, the limiting reactant;

63.5 g of Cu reacts with 170 * 2 g of AgNO3,

19 g of Cu will react with (340 * 19)/63.5 g of AgNO3 =101.7 g of AgNO3.

Since there are 125 g of AgNO3 available for reaction, it is in excess and Cu is the limiting reactant.

63.5 g of Cu reacts to produce 108 * 2 g of Ag,

19 g of Cu will react to produce (216 * 19)/63.5 g of Ag = 64.6 g of Ag.

Therefore mass of Ag produced = 64.6g

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