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aivan3 [116]
3 years ago
11

A flexible container at an initial volume of 8.15 l contains 6.51 mol of gas. more gas is then added to the container until it r

eaches a final volume of 12.7 l. assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Chemistry
1 answer:
kirill [66]3 years ago
3 0
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
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What is the mass of 2.15 liters of N2 gas at STP?
devlian [24]

Answer:

2.68g

Explanation:

Given parameters:

Volume of gas at STP = 2.15L

Unkown:

Mass of Nitrogen N₂ gas at STP = ?

Solution

To find the mass of the gas at STP, we use the mole concept approach.

In using the mole approach we follow the following procedures:

1. Find the number of moles of gas at STP using the relationship below:

                  Number of moles = \frac{volume occupied}{22.4dm^{3} mol^{-1} }

                         Note: 1L = 1dm³

2. Then using the mole and mass relationship, we can find the mass of the gas using the equation below:

                Mass = number of moles x molar mass

Workings

1.              Number of moles of N₂ = \frac{2.15}{22.4}

                Number of moles of N₂ = 0.096mole

2. Given that the atomic mass of N = 14g

                       Molar mass of N₂ = 2 x 14 = 28gmol⁻¹

Mass = 0.096mol x  28gmol⁻¹ = 2.68g

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3 years ago
Write the correct answers.
Ilya [14]

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Determine the molecular formulas of these compounds:
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The molecular formulas of the empirical ones of P₂O₅ and CH₂O are P₄O₁₀ and C₇H₁₄O₇, respectively, knowing that their molar masses are 310 and 200.18 g/mol, respectively.  

<h3>1. Molecular formula of P₂O₅</h3>

We can calculate the molecular formula as follows:

MF = n*EF   (1)

Where:

  • MF: is the molecular formula
  • EF: is the empirical formula
  • n: is an integer  

To calculate the integer <em>n</em>, we need to use the following equation:

n = \frac{M}{M_{EF}}   (2)

Where:

  • M: is the molar mass of P₂O₅ =  310 g/mol
  • M_{EF}: is the molar mass of the empirical formula

The molar mass of the empirical formula of P₂O₅  is given by:

M_{EF} = 2A_{P} + 5A_{O}

Where:

  • A_{P}: is the atomic weight of phosphorus = 30.974 g/mol
  • A_{O}: is the <em>atomic weight</em> of oxygen = 15.999 g/mol

So, the <em>molar mass</em> of the <em>empirical formula</em> of P₂O₅  is:

M_{EF} = (2*30.974 + 5*15.999) g/mol = 141.943 g/mol  

Now, we can find the integer <em>n </em>(eq 2).

n = \frac{M}{M_{EF}} = \frac{310 \:g/mol}{141.943 \:g/mol} = 2  

Finally, after multiplying the integer <em>n</em> by the number of atoms on the empirical formula of P₂O₅, we have (eq 1):

MF = n*EF = 2 \times P_{2}O_{5} = P_{(2 \times 2)}O_{(5 \times 2)} = P_{4}O_{10}

Therefore, the molecular mass of P₂O₅ is P₄O₁₀.

<h3>2. Molecular formula of CH₂O   </h3>

We know:

  • M: molar mass of CH₂O = 200.18 g/mol

To calculate the integer <em>n</em> and so the molecular mass of the molecule, we need to calculate the<em> molar mass</em> of the <em>empirical formula</em> of CH₂O.

M_{EF} = A_{C} + 2A_{H} + A_{O} = (12.011 + 2*1.008 + 15.999) g/mol = 30.026 \:g/mol

 

Now, the integer <em>n </em>is equal to (eq 2):

n = \frac{M}{M_{EF}} = \frac{200.18 g/mol}{30.026 g/mol} \approx 7

Finally, the molecular formula of the molecule is (eq 1):

MF = n*EF = 7 \times CH_{2}O = C_{(1 \times 7)}H_{(2 \times 7)}O_{(1 \times 7)} = C_{7}H_{14}O_{7}                              

Therefore, the molecular formula of CH₂O is C₇H₁₄O₇.

Learn more about molecular formula here:

  • brainly.com/question/1247523
  • brainly.com/question/14327882

I hope it helps you!

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radio waves,  micro waves, infrared waves, visible light rays, ultra-violet rays, x-rays, then finally, gamma rays. I hope this was helpful to you.

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A biotic factor in a desert ecosystem would be the
valkas [14]
C is correct.

Please vote my answer brainliest. thanks!
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