Question

Quadrilateral ABCD has vertices A(−2,1), B(4,4), C(5,0), and D(−1,−2).

Answer 1

Using the distance formula,  $\sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}$ to find the length of each sides, the longest side is about 6.71 units which is: d. AB

To find the longest side, we would apply the distance formula to find the length of each side.

Given:

• A(−2,1)
• B(4,4)
• C(5,0)
• D(−1,−2)

Distance formula = $\sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}$

Length of AB:

• Let,

$A(-2,1) = (x_1, y_1)\\\\B(4,4) = (x_2, y_2)$

• Substitute

$AB = \sqrt{(4 - 1)^2 + (4 - (-2))^2}\\\\AB = \sqrt{9 + 36}\\\\AB = \sqrt{45} \\\\AB = 6.71$

Length of BC:

• Let,

$B(4,4) = (x_1, y_1)\\\\C(5,0) = (x_2, y_2)$

• Substitute

$BC= \sqrt{(0-4)^2 + (5-4)^2}\\\\BC = \sqrt{16 + 1}\\\\BC = \sqrt{17} \\\\BC =4.12$

Length of CD:

• Let,

$C(5,0) = (x_1, y_1)\\\\ D(-1,-2) = (x_2, y_2)$

• Substitute

$CD = \sqrt{(-2 - 0)^2 + (-1 - 5)^2}\\\\CD = \sqrt{4 + 36}\\\\CD = \sqrt{40} \\\\CD =6.32$

Length of DA:

• Let,

$D(-1,-2) = (x_1, y_1)\\\\ A(-2,1) = (x_2, y_2)$

• Substitute

$DA = \sqrt{(-2 - 1)^2 + (-1 - (-2))^2}\\\\DA= \sqrt{9 + 1}\\\\DA = \sqrt{10} \\\\DA = 3.16$

Therefore, the using the distance formula,  $\sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}$ to find the length of each sides, the longest side is about 6.71 units which is: d. AB

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Answer 2

Step-by-step explanation:

Refer to the attachment ♪♪