Answer:
-4 to 3
Step-by-step explanation:
look at the first number in each set then find the smallest and the biggest that is how you find range
Step-by-step explanation:
There is no option to choose from, but the knowledge of what irrational numbers are, would help cover this cost.
A rational number is a number that can be written as a simple fraction, a/b. Examples are 1/2, 5/6,...
If a number cannot be written as a simple fraction, then it is called irrational.
Example of irrational numbers: √2, π
Answer:
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a certain hockey team will win any given game is 0.3723
So 
12 games in November
So 
What is the probability that the hockey team wins 6 games in November?
This is 
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Answer:
930 dollars
Step-by-step explanation:
Let software programs = S
Video game = V
Given that a company makes a profit of $7 per software program that is, 7S and $8 per video game that is, 8V. The company can produce at most 90 software programs and at most 80 video games per week. Since the Total production cannot exceed 120 items per week.
How many items of each kind should be produced per week in order to maximize the profit?
The to get profit P
P = 7S + 8V
Since the profit on video game is higher, we will give maximum production to video game. Therefore,
P = (30 × 7) + ( 8 × 90)
P = 210 + 720
P = 930 dollars
