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earnstyle [38]
3 years ago
12

What percent is 25/75?

Mathematics
2 answers:
DaniilM [7]3 years ago
5 0

Answer:

33.33%

Step-by-step explanation:

Snezhnost [94]3 years ago
4 0

Answer:

33.3333%

explaination

When we are using percentages, what we are really saying is that the percentage is a fraction of 100. "Percent" means per hundred, and so 50% is the same as saying 50/100 or 5/10 in fraction form. Now we can see that our fraction is 33.333333333333/100, which means that 25/75 as a percentage is 33.3333%

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A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
Hamster111 yes please
Rufina [12.5K]

Answer:

Indeed

Step-by-step explanation:

3 0
3 years ago
Find the value of x ​
Kay [80]

Answer:

11

Step-by-step explanation:

\left(6x+4\right)+10x=180

16x+4-4=180-4

16x=176

\frac{16x}{16}=\frac{176}{16}

x=11

6 0
3 years ago
Add: (-5u5 + 5) + 7u5
balu736 [363]

Answer:

2u^5+5

Step-by-step explanation:

Drop parenthesis and add like terms.

7u^{5}-5u^{5}+5=2u^{5}+5

Hope this helps!

If not, I am sorry.

7 0
2 years ago
Write an explicit rule to represent the sequence:
lisov135 [29]

Answer:

b)f(n)=4n+16

Step-by-step explanation:

if n=1

substitute 1 for n in the equation

f(1)=4(1)+16

=4+16

=20

f(2)=4(2)+16

=8+16

=24

And so on

6 0
2 years ago
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