Recall that 
.
If you know the Maclaurin series for
, finding this expansion should be easy.
If you know the Maclaurin series for
Solve for n: 4(nP3) = 5(n-1P3)
1 answer:
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Answer:
a. Check the attached image
b. The Pr(Y > 2) = ½
c. The mean is 2.4
d. The standard deviation is: 2.72
e. The exact value is 1 because it is certain from the given data that any probability will fall within that range.
Step-by-step explanation:
a. An image showing the step by step solution is attached.
b. P(Y > 2) = P(3) + P(4)
= 2/10 + 3/10 = 5/10 = ½
c. The mean is 2.4
d. The standard deviation is: 2.72
e. Check the attached image for the steps.
