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LekaFEV [45]
3 years ago
6

I need help plz in opt math..plzz​

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

the value of y=2

here ,

(2x-1,3y-2)=(x+2,2y)

then,

3y-2=2y{corresponding elements}

3y-2y=2

or, y=2

hence the value of y=2

Dafna11 [192]3 years ago
8 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

Value of the given terms are :

  • x = 3

  • y = 2

Solution is in attachment ~

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X3 - 3y when x=6 and y= -3
quester [9]

Answer:

9

Step-by-step explanation:

6×3=18 3×3=9 9+18

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3 0
3 years ago
There are 25 girls going to Hershey Park for chorus.
Lunna [17]

Answer:

Solution given:

total no of girls [g]=25

let no of boys [b]=b

according to the question

g=2b+3

25-3=2b

b=22/2

b=11

<u>total number of boys going to Hershey Park is 11</u><u>.</u>

5 0
3 years ago
my son is 7 times older than my grandson and i am 12 times older than my grandson .if you added all of our ages together the sum
Ludmilka [50]
The equation would be x+7x+12x = 100
solving gives x=5
12×5=60
7×35

5+35+60=100

The age/answer is 60
8 0
3 years ago
Read 2 more answers
Here are 7 numbers.
SIZIF [17.4K]

Answer:

3.06

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4 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
Furkat [3]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

3 0
3 years ago
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