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djyliett [7]
3 years ago
14

A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t^2 + 608t. After how many seconds

does it reach its maximum height? A. 38 s
B. 19 s
C. 28.5 s
D. 9 s
Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer: 19 seconds

Step-by-step explanation:

The equation used to represent the height of the projectile above the ground after t seconds is expressed as

h = -16t^2 + 608t.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the projectile.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 608

Vertex = - - 608/32= 19

So the projectile will attain maximum height at 19 seconds.

nordsb [41]3 years ago
5 0

Answer:

I think the answer to your question is 19 seconds because if you do the math you get a vertex

Step-by-step explanation:

Using a calculator

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Step-by-step explanation:

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6 0
3 years ago
A 95-foot wire attached from the top of a cell phone tower makes a 62 degree angle with the ground. Joey is standing 150 feet be
a_sh-v [17]

Answer:

23.32 degrees

Step-by-step explanation:

We set up a large right triangle that has 2 triangles within it.  The large triangle is a right triangle.  The height of it is the height of the tower, the base angle is 62, the hypotenuse is 95, and the base measure is y.  The other triangle has the same height which is the height of the tower, the angle is what we are looking for, and the base measure is 150 feet beyond y, so its measure is y + 150.  We have enough information to find the height of the tower, so let's do that first.  Going back to the first smaller triangle.  

sin62=\frac{x}{95} so the height of the tower is 83.88 feet.  Now we need to solve for y.  Using that same triangle and the tangent ratio, we find that tan62=\frac{83.88}{y}.  Now let's do the same thing for the other triangle with the unknown angle.

tan\beta =\frac{83.88}{y+150}

Solve both of these for y.  The first one solved for y:

y=\frac{83.88}{tan62}

The second one solved for y will simplify to:

y=\frac{83.88-150tan\beta }{tan\beta }

Now that these are both solved for y, and y = y, we can set them equal to each other by the transitive property of equality:

\frac{83.88-150tan\beta }{tan\beta }=\frac{83.88}{tan62}

Cross multiply to get this big long messy looking thing:

tan62(83.88-150tan\beta )=83.88tan\beta

Distribute through the parenthesis to get

83.88tan62-[(tan62)(150tan\beta)]=83.88tan\beta

Get the unknown angles on the same side so it can be factored out:

83.88tan62=83.88tan\beta +[(tan62)(150tan\beta )]

And then factoring it out gives you:

83.88tan62=tan\beta(83.88+150tan62)

Divide to get

tan\beta =\frac{83.88tan62}{83.88+150tan62}

Do this on your calculator in degree mode to give you an angle measure of 23.32°.  I know this is really hard to follow without being able to draw the pics for you like I do in my classroom, but hopefully you can follow my description and draw your own triangles and follow from that!

4 0
3 years ago
2(n+2)=10 solve for n
astra-53 [7]

Answer :

<em>\:  \:  \:  \:  \:  \: 2(n + 2) = 10 \\  =  > 2n + 4 = 10 \\  =  > 2n = 10 - 4 \\  =  > 2n = 6 \\  =  > n =  \frac{6}{2}  \\   = > n = 3</em>

5 0
3 years ago
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