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djyliett [7]
3 years ago
14

A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t^2 + 608t. After how many seconds

does it reach its maximum height? A. 38 s
B. 19 s
C. 28.5 s
D. 9 s
Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer: 19 seconds

Step-by-step explanation:

The equation used to represent the height of the projectile above the ground after t seconds is expressed as

h = -16t^2 + 608t.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the projectile.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 608

Vertex = - - 608/32= 19

So the projectile will attain maximum height at 19 seconds.

nordsb [41]3 years ago
5 0

Answer:

I think the answer to your question is 19 seconds because if you do the math you get a vertex

Step-by-step explanation:

Using a calculator

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Step-by-step explanation:

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3 years ago
Consider h(x)=x^2+8+15. identify its vertex and y-intercept.
OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, [x = \frac{-b}{2a}, h(\frac{-b}{2a})].

<h3>Use the equation:  [x = \frac{-b}{2a}, h(\frac{-b}{2a})]</h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

x = \frac{-b}{2a}

x = \frac{-8}{2(1)}

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

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Step-by-step explanation:

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Step-by-step explanation:

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kenny6666 [7]

Answer:

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Step-by-step explanation:

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