Question

A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t^2 + 608t. After how many seconds does it reach its maximum height? A. 38 s
B. 19 s
C. 28.5 s
D. 9 s

Answer 1

Answer: 19 seconds

Step-by-step explanation:

The equation used to represent the height of the projectile above the ground after t seconds is expressed as

h = -16t^2 + 608t.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the projectile.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 608

Vertex = - - 608/32= 19

So the projectile will attain maximum height at 19 seconds.

Answer 2

Answer:

I think the answer to your question is 19 seconds because if you do the math you get a vertex

Step-by-step explanation:

Using a calculator