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maw [93]
3 years ago
10

You are comparing the viewing area of two televisions at the local store. The cheaper version has a length that is 1 foot greate

r than its width The more expensive version gives
you an additional 0.5 feet to both dimensions. Which equation represents the new viewing area, N, of the larger television
Mathematics
1 answer:
Annette [7]3 years ago
5 0
Width of smaller tv=x. in feet
length of smaller tv =x+1
l of larger= x+1.5
w of larger = x +0.5
area = l x w
area = (x+1.5)(x+ 0.5)
area= x^2 +2x + 0.75
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The correct answer for 12 is B
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grandymaker [24]

Answer:

2 minutes.  

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: x-\frac{2}{5}.

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that \text{Time}=\frac{\text{Distance}}{\text{Speed}}, so we can set two equations for time taken by Achilles and turtle as:

t=\frac{x}{13}...(1)

t=\frac{(x-\frac{2}{5})}{1}...(2)

From equation (1) we will get,

x=13t

Upon substituting this value in equation (2) we will get,

t=\frac{13t-\frac{2}{5}}{1}    

Let us have a common denominator.  

t=\frac{\frac{65t-2}{5}}{1}

t=\frac{65t-2}{5}

Upon multiplying both sides of our equation by 5 we will get,

5t=5\times \frac{65t-2}{5}

5t=65t-2

5t-65t=65t-65t-2

-60t=-2

t=\frac{-2}{-60}

t=\frac{1}{30}

So, the competition took 1/30 hour, let us convert our given time in minutes.

\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}

\frac{1}{30}\times 60\text{ minutes}

2\text{ minutes}  

Therefore, the competition took 2 minutes.


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3 years ago
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earnstyle [38]

Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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O 1.7 x 102 meters  =    170 meters      [Loser]

O 1.8 x 103 meters  =  1800 meters

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