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lord [1]
3 years ago
10

Valerie is making identical quilts for herself and her sister. For each quilt she buys 5 yards of solid fabric and w yards of pr

inted fabric. If w = 4, how much fabric did Valerie buy to make both quilts? ( _____) x 2; ______
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0
Valerie bought 18yrds of fabric. If she used 9yrds of fabric on her quilt, she will use another 9yrds on her sister's. The total is 18yrds.
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Calculate the unpaid balance, finance charge, and new balance using the unpaid balance method. Note: interest rate is given as a
Karolina [17]

Answer:

The new balance will be $385.04.

Step-by-step explanation:

Previous balance = $179.32

Payments/credits = $85.00

Unpaid balance = 179.32+85 = $264.32

Monthly rate = 1.25%

Finance charge = 0.0125\times264.32 = $3.30

New purchases = $117.42

New balance = 264.32+3.30+117.42 = $385.04

5 0
3 years ago
Read 2 more answers
A paper company needs to ship paper to a large printing business. The a paper will be
eimsori [14]

Given :

A paper company needs to ship paper to a large printing business.

The paper will be shipped in small boxes and large boxes.

Each small box of paper weighs 50 pounds and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Find :

Determine the number of small boxes shipped and the number of large boxes shipped.

Calculations :

Let "S" be small boxes and "L" be large boxes.

Small box + Large box = 19

50S + 80L = 1280

→ 5S + 8L = 128

→ 5 (19 - L) + 8L = 128

→ 3L = 128 - 95

→ L = 33/3

→ L = 11ㅤㅤ

Finding the small box:

→ S = 19 - L

→ S = 19 - 11

→ S = 8

Therefore ,

Large boxes = 11.

Small boxes = 8.

orrrrrr

The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Let there are x small boxes and y large boxes.

Then,

x + y = 19 ............ (1) and

50x + 80y = 1280

⇒ 5x + 8y = 128 ............... (2)

Now, solving equations (1) and (2) we get,

5( 19 - y) + 8y = 128

⇒ 3y = 128 - 95 = 33

⇒ y = 11

Now, from equation (1) we get, x = 19 - y = 19 - 11 = 8

Therefore, the number of small boxes is 8 and that of the large boxes is 11. (Answer)

8 0
3 years ago
I need answers for number 20 I need This done by Tuesday
nikdorinn [45]

One ticket costs $24.50 - $19 more for evening

Six tickets cost 6 (  $24.50 - $19 ) more

Answer: 6 (  $24.50 - $19 )

Problem 18 is D by the way

6 0
3 years ago
If the radius of a circle is 10 feet, how long is the arc subtended by an angle measuring 81°?
Kaylis [27]
<span>The length of an arc, L = theta/360 * 2 * pie * r Where theta = 81 and r = 10ft = 3.048m So length = 81/360 * 2 * pie * 3.048 L = * 0.225 * 2 * pie * 3.048 L = 1.37 * pie L = pie. Option A</span>
4 0
3 years ago
Im stuck on this question, plz help
denis-greek [22]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

40 metres covered in 6 seconds

Max speed attained after 6seconds

75 meters covered after 11 seconds

Average Speed for first 40 meters :

Speed = distance / time

Speed = 40m / 6s

Speed = 6.67m/s

To obtain the maximum speed :

Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds

Speed at this point is maximum :

Hence, maximum speed = (35m / 5s) = 7m/s

Suppose, Manuel runs for an additional z seconds after reaching max speed :

Distance from starting line 6+z seconds after race started?

Distance after 6 seconds = 40 metres

Distance after z seconds = 7 * z

Total distance = (40 + 7z)

What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?

Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))

40 + 7(x - 6)

3 0
3 years ago
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