Answer:
1) 
2) 
3) 
And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
4) 
And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be:
Step-by-step explanation:
For this case we have the following distributions given:
Probability M J
0.3 14% 22%
0.4 10% 4%
0.3 19% 12%
Part 1
The expected value is given by this formula:

And replacing we got:

Part 2

Part 3
We can calculate the second moment first with the following formula:

And the variance would be given by:
![Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89](https://tex.z-dn.net/?f=Var%20%28M%29%3D%20E%28M%5E2%29%20-%5BE%28M%29%5D%5E2%20%3D%20207.1%20-%2813.9%5E2%29%3D%2013.89)
And the deviation would be:
Part 4
We can calculate the second moment first with the following formula:

And the variance would be given by:
![Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56](https://tex.z-dn.net/?f=Var%20%28J%29%3D%20E%28J%5E2%29%20-%5BE%28J%29%5D%5E2%20%3D%20194.8%20-%2811.8%5E2%29%3D%2055.56)
And the deviation would be:
<em>Greetings from Brasil...</em>
Be that unknown number X
Then we can write the following expression:
X + 4.7 = 8.1
<h2>X = 3.4</h2>
Answer:
1-6 you need to write the JHI DEF where the radius center point is in the middle of each shape next to 1-6 some have 2 shapes so use 6 letters there.
Step-by-step explanation:
1. Area = 72 of 360 = 20% of 716.3 = 143.26inch*2 =JHI
2.Area = 19 of 360 = 68.4% of 69.4 = 47.46km^2 =DEF
3. Area = 92 of 360 = 25.56% of 153.9 = 39.33cm^2
4. Area = 226 of 360 = 64.57% of 706.9 = 456.45ft^2
5. Area = 74 of 360 = 20.55% of 153.9 =31.63 inch^2
6. Area = 326 of 360 = 90.56% of 1452 -137.07 = 1314.93m^2