Question

If b varies jointly with c and the square root of d, and b= 12 when c=8 and d = 9, find b when c = 11 and d = 25

Answer 1

Step-by-step explanation:

b varies directly to c and square root of d

K is the constant

b=c

b=c/√d

b=Kc/√9

12= 8k/√9

12=8k/3

we crossed multiply

12*3=8k

36=8kb

we divide both sides by 8

K= 36/8

K= 18/4

K= 9/2

Go back to the equation

b=Kc/√d

b=9/2(11)/√25

b= 99/2/5

b= 49.5/5

b= 9.9 or b=10