Answer:
ok? whats the question Imao
Step-by-step explanation:
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Since 10 cm is bigger than 1 mm, the scale drawing is bigger
Given:
In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.
To find:
The measure of side PQ.
Solution:
In ΔOPQ,
[Angle sum property]
According to Law of Sines, we get
Using the Law of Sines, we get
Substituting the given values, we get
Approximate the value to the nearest tenth of a foot.
Therefore, the length of PQ is 2.4 ft.
Answer:
c
Step-by-step explanation: not much has change the perminater will always stay the same
