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2 years ago

Mariah’s parents got into a car accident. They took their car to the

Mathematics

1 answer:

KatRina [158]2 years ago

5 0

Answer: The mechanics spent about 8.5 hours working on the car

Step-by-step explanation: The total bill was $637, a portion of that being getting the parts which was $280. 637-280=357

357/42=8.5

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Se quieren llenar 100 botellas de agua con una capacidad de 1/4lt ¿cuantos litros de agua son necesarias?

Mrac [35]

Answer:

Step-by-step explanation:

Because 100 25+25+25+25 or 25/1/4

7 0

1 year ago

Please help me finish these for summer school :)

ValentinkaMS [17]

13.45 will be the answer

since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2

this will then be 10^2 + 9^2 = c^2

181=c^2

c=13.45 :)

5 0

2 years ago

Read 2 more answers

-13 + 24-46-( - 20 ) =

Naddik [55]

Answer

-15

Step-by-step explanation:

-13 +24=11

11-46=-35

-35+20=-15

3 0

2 years ago

Read 2 more answers

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).