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Brilliant_brown [7]
3 years ago
14

Click on file! please help, thank you!! <3​

Mathematics
1 answer:
Elden [556K]3 years ago
7 0
15+3x-4+6x= 9x+11 add 6+3 then subtract 15-4

3y-4x+8x-y= 4x+2y add -4+8 then subtract 3-1

5x+8x+10x-3x= 20x Add 10+5+8 to get 23 then subtract 3
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Read 2 more answers
Help Review of linear pair vertical and complementary
Lera25 [3.4K]

Answer:

x = 15

Step-by-step explanation:

The two angles form a straight line so they add to 180 degrees

3+6x   + 5x+12 = 180

Combine like terms

11x+15 = 180

Subtract 15 from each side

11x+15-15 =180-15

11x = 165

Divide by 11

11x/11 =165/11

x =15

7 0
3 years ago
Which equation is represented by the graph below?
Andrews [41]

Answer:

B

Step-by-step explanation:

When x = 1, it appears y is in between 1 and 2.

The only choice that satisfies this is B.

5 0
2 years ago
Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
9966 [12]

L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

5 0
4 years ago
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