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AnnZ [28]
3 years ago
9

Give the domain and range.

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

Domain: {-3, 0 3}

Range: {0, 3}

Step-by-step explanation:

Recall that the Domain of a relationship associated with coordinate pairs of the form (x,y), is the set of all "x-values" given in the relationship.

The Range is the set of all "y-values" given in the relationship.

In our case, we have three coordinate points defining the relationship. These points have the following (x,y) coordinates (see attached image to see which coordinates are associated with each point):

(-3, 3), (0, 0), and (3, 3)

Therefore, the x values associated with these points are: -3, 0 and 3

therefore the Domain of the relationship is the set: { -3, 0, 3}

On the other hand, he y values associated with these points are: 3, 0, and again 3. So in fact there are just to distinct y-values: 0 and 3.

therefore the Range of the relationship is he set: {0, 3}

which corresponds to answer B.

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Lera25 [3.4K]

Answer:

y = -5

x = 2

Step-by-step explanation:

The computation is show below:

Given that

-6x - 6y = 18

6x - 3y = 27

Now if we solved both equation so

-9y = 45

y = -5

And, x is

-6x - 6(-5)  = 18

-6x + 30 = 18

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x = 2

3 0
3 years ago
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Crank
Yes if he practices X amount of hours and is told to practice X amount of hours than he practiced long enough
4 0
4 years ago
PLEASE HELP I HAVE BEEN TRYING TO FIGURE THIS OUT FOR 4 HOURS AND 15 MINUTES
harkovskaia [24]

Answer:

1. C) 3

2. D) -1

3. D) 7^2 - 8*2 - 16

4. B) 75

5. B) 6^2 + (2 - 8)*sqrt(81)

Step-by-step explanation:

1. (10 - (6-4)^2)/2

= (10 - 2^2)/2

= (10 - 4)/2

= 6/2

= 3

2. PEMDAS states that Multiplication is before Subtraction

8 - (5^2-7)/2

= 8 - (25-7)/2

= 8 - 18/2

= 8 - 9

= -1

3. D) 7^2 - (8*2) - 16

= 49 - 16 - 16

= 49 - 32

= 17

4. 3(2 + 3)^2

= 3(5)^2

= 3(25)

= 75

5. 6^2 + (2 - 8)*sqrt(81)

= 36 + (-6*9)

= 36 - 54

= -18

5 0
3 years ago
Writing: A mistake has been made in the solution. Explain the error and how to correct it.
Liono4ka [1.6K]

Answer:

The mistake was made in the second step when going from 3x - 2(3x-4) = 13 to 3x - 6x - 8 = 13.

The mistake was in the multiplication of -2(3x-4). The error is that the negative sign was not distributed to both the 3x and the -4.

-2 times 3x is -6x  and  -2 times -4 is positive 8

Step-by-step explanation:

y = 3x - 4

3x - 2y = 13

------------------------

3x - 2(3x - 4) = 13

3x - 6x + 8 = 13

-3x + 8 = 13

-3x = 5

x = -5/3

y = 3(-5/3) - 4

y = -5 - 4

y = -9

Solution: x = -5/3 and y = -9

3 0
3 years ago
Given the formula C= 1/2t(c1-c2), solve for t.
kobusy [5.1K]

Answer:

t=\frac{2C}{c1-c2}

Step-by-step explanation:

C=\frac{1}{2}t(c1-c2)\\2(C)=2(\frac{1}{2}t(c1-c2))\\2C=t(c1-c2)\\\frac{2C}{c1-c2}=\frac{t(c1-c2)}{c1-c2}\\t=\frac{2C}{c1-c2}

3 0
3 years ago
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