3 years ago

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Mathematics

1 answer:

Step2247 [10]3 years ago

8 0

Answer:

You could look it up on goo gle that is what I do

Step-by-step explanation:

PLZ MARK ME BRAINLYIST

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Step-by-step explanation:

Let x = smaller number , y= larger number.

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$\dfrac{y}{3}+y=y^2-5\\\\\Rightarrow\ \dfrac43y=y^2-5\\\\\Rightarrow\ 3y^2-4y-15=0\\\\\Rightarrow\ 3y^2-9y+5y-15=0\\\\\Rightarrow\ 3y(y-3)+5(y-3)=0\\\\\Rightarrow\ (y-3)(3y+5)=0\\\\\Rightarrow\ y=3 \ \ or\ y=\dfrac{-5}{3}$

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