Use the Foil Method:
First: t x t =t^2
Outsides: t x 8 = 8t
Insides: -1 x t = - t
Lasts: 8 x -1 = -8
so you'll have t^2 + 8t - t - 8, simplify it more: t^2 + 7t - 8, A.
Thr probability is calculated from the data gathered from tests on a large number of people. There's undoubtedly some data included with this question that you neglected to copy. Without it, it's not possible to come up with an answer.
Answer:
The volume of the solid is 
Step-by-step explanation:
In this case, the washer method seems to be easier and thus, it is the one I will use.
Since the rotation is around the y-axis we need to change de dependency of our variables to have 
. Thus, our functions with 
as independent variable are:
For the washer method, we need to find the area function, which is given by:
![A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]](https://tex.z-dn.net/?f=A%3D%5Cpi%5Ccdot%20%5B%28%5Crm%7Bouter%5C%20radius%29%5E2%20-%28%5Crm%7Binner%5C%20radius%29%5E2%20%5D)
By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function 
and the inner one by 
. Thus, the area function is:
![A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)](https://tex.z-dn.net/?f=A%28y%29%3D%5Cpi%5Ccdot%20%5B%28%5Csqrt%7By%7D%20%29%5E2-%28y%5E2%29%5E2%5D%5C%5CA%28y%29%3D%5Cpi%5Ccdot%20%28y-y%5E4%29)
Now we just need to integrate. The integration limits are easy to find by just solving the equation 
, which has two solutions 
and 
. These are then, our integration limits.
Answer:
determine current financial situation
develop your financial goals
identify alternative course of action
evaluate alternatives
Create and implement your financial action plan
review and revise the financial plan.
Hope this helps have a great day! btw I have a question plz help me its due tonight.
Sine you know that the angle is eighty, you could use twenty times sin80. Sin 80 represents opposite of hypotenuse, so 20 is the hypotenuse, canceling the denominator out giving the height only.
