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Irina18 [472]
3 years ago
9

Evaluate (4/3)³×(4/3)‐²×(1/3)​

Mathematics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

256/243

Step-by-step explanation:

64/27 x 4/3 x 1/3

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Circle 1 is centered at (−4,5) and has a radius of 2 centimeters. Circle 2 is centered at (2,1) and has a radius of 6 centimeter
Crazy boy [7]
<span>To show that Circle 1 and Circle 2 are similar the  Translation </span>and Dilation <span> should be applied. 
</span><span>Transformation rule (2-(-4),(1,-5) ) =(6,-4)and then dilate it using a scale factor of (6/2=3).
</span>
Transformation rule (6,-4)and then dilate it using a scale factor of (3).
7 0
3 years ago
Annie, Brianna &amp; Carly are selling fruit boxes to raise money for their soccer team. All together the girls have sold 105 bo
GaryK [48]

Step-by-step explanation:

Annie = x

Brianna = y

Carly = z

Now,

x + y + z = 105 ...(1)

Carly has sold ten more than three times Brianna's sales.

z = 10 + 3y ...(2)

Brianna sold five more than Annie.

y = 5 + x ...(3)

Now,

z = 10 + 3y

z = 10 + 3(5 + x)

z = 10 + 15 + 3x

z = 25 + 3x

Now,

x + y + z = 105

x + (5 + x) + 25 + 3x = 105

5x + 30 = 105

5x = 105 - 30

5x = 75

5x/5 = 75/5

x = 15

So,

y = 5 + x

y = 5 + 15

y = 20

Now,

z = 25 + 3x

z = 25 + 3(15)

z = 25 + 45

z = 70

Thus,

Annie Sold 15 boxes

Brianna Sold 20 boxes

Carly Sold 70 boxes

6 0
2 years ago
Jupiter orbits the sun at a rate of 8 miles per second. How far does Jupitertravel in one day? Tip: There are 86400 seconds in a
gulaghasi [49]

Answer:

Jupiter travels 691200 miles a day

Step-by-step explanation:

I just did 86400 x 8

Plz give brainliest

5 0
3 years ago
you have 148 feet of fencing to enclose a rectangular region. What is the maximum area of the region?
Nikitich [7]

4x37

Step-by-step explanation:

only a few ways to get to 148

4 0
3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
3 0
3 years ago
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