Helen and Ivan had the same number of coins. Helen had a number of 50-cent coins, and 64 20-cent coins. These coins had a mass o
1 answer:
Answer:
Step-by-step explanation:
Let H stand for the total number of Helen's coins and I for the total number of Ivan's coins.
We are told that H = I
We also know that Helen has 64 20-cent coins. The total mass of her coins, H, is 1.134kg.
Ivan has 104 20-cent coins.
We are told that both have a non-defined number of 50-cent coins.
(a) Who has more money in coins and by how much?
Since both have an equal number of coins, but Ivan has more 20-cent coins than Helen, Helen must therefore have a greater number of 50-cent coins, making her the richest of the two.
Helen has (H - 64) 50-cent coins
I has (I - 104) 50-cent coins
Since H=I, the ratio of Helen's to Ivan's 50-cent coins is (H-64)/(H-104)
But it is here that I don't know how to calculate the total value of coins, without more information. All I know is that both have a known number of 20-cent coins, but I don't see an upper limit to the number of 50-cent coins.
Let's assume both had 200 coins. The breakdown is shown in the attachment.
Sorry, I may see the answer tomorrow, but I need to leave now.
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