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BartSMP [9]
3 years ago
13

If 1 1/2 cups of cereal weigh 2 pounds, how much does 1 cup of cereal weigh?

Mathematics
1 answer:
GrogVix [38]3 years ago
8 0
1.5 / 2 = 1 / x # cups / weight = # cups / weight 

<span>cross multiply </span>
<span>1.5x = 2 </span>

<span>divide both sides by 1.5 </span>

<span>x = 1.3(the 3 keeps going) or 1 and 1/3 pounds 
So the answer is 1/3
 
</span><span>please mark as brainlyest, comment, 5 stars and give a thanks!!</span>
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3 years ago
Read 2 more answers
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
F(x) = x^2 + x - 11
Stella [2.4K]

Answer: y = − \frac{39}{4}

Step-by-step explanation:

8 0
2 years ago
I don’t know how to do this
zalisa [80]

Answer:

½÷3=0.17

if you're talking about the app, i don't get too

7 0
2 years ago
Please help quickly !!
Nataly_w [17]

Answer:

16.5x == 465.3

Step-by-step explanation:

To find the rate , take the number of miles and divide by the gallons

rate = 465.3 / 16.5

Let the rate be x

x = 465.3 / 16.5

Multiply each side by 16.5

16.5x =  465.3

6 0
3 years ago
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