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2 years ago

If the points below represent a direct variation, find the missing value (5,14)and (x,28)

Mathematics

1 answer:

bekas [8.4K]2 years ago

8 0

X = 10. 14 x 2 = 28. 5 x 2 = x

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Please help thank you

Dvinal [7]

the tale-tell fellow is the number inside the parentheses.

if that number, the so-called "growth or decay factor", is less than 1, then is Decay, if it's more than 1, is Growth.

$\bf f(x)=0.001(1.77)^x\qquad \leftarrow \qquad \textit{1.77 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(1.5)^{\frac{x}{2}}\qquad \leftarrow \qquad \textit{1.5 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=5(0.5)^{-x}\implies f(x)=5\left( \cfrac{05}{10} \right)^{-x}\implies f(x)=5\left( \cfrac{1}{2} \right)^{-x} \\\\\\ f(x)=5\left( \cfrac{2}{1} \right)^{x}\implies f(x)=5(2)^x\qquad \leftarrow \qquad \textit{Growth} \\\\[-0.35em] ~\dotfill$

$\bf f(t)=5e^{-t}\implies f(t)=5\left( \cfrac{e}{1} \right)^{-t}\implies f(t)=5\left( \cfrac{1}{e} \right)^t \\\\\\ \cfrac{1}{e}\qquad \leftarrow \qquad \textit{that's a fraction less than 1, Decay}$

now, let's take a peek at the second set.

$\bf f(x)=3(1.7)^{x-2}\qquad \leftarrow \qquad \begin{array}{llll} \textit{the x-2 is simply a horizontal shift}\\\\ \textit{1.7 is more than 1, Growth} \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3(1.7)^{-2x}\implies f(x)=3\left(\cfrac{17}{10}\right)^{-2x}\implies f(x)=3\left(\cfrac{10}{17}\right)^{2x} \\\\\\ \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill$

$\bf f(x)=3^5\left( \cfrac{1}{3} \right)^x\qquad \leftarrow \qquad \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3^5(2)^{-x}\implies f(x)=3^5\left( \cfrac{2}{1} \right)^{-x}\implies f(x)=3^5\left( \cfrac{1}{2} \right)^x \\\\\\ \textit{that fraction in the parentheses is less than 1, Decay}$

6 0

3 years ago

Solve the equation-30=j+50

andreyandreev [35.5K]

J=(-80) hope this helps! don’t forget to mark Brainliest.

5 0

2 years ago

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Answer? I’m struggling

Dennis_Churaev [7]

a. $3\frac{11}{12}$

b. $\frac{4}{3}$

3 0

2 years ago

Please help! Math problem is attached!!

Tamiku [17]

Answer:

Ounces of strawberry juice: 20 ounces

Ounces of water: 80 ounces

Step-by-step explanation:

For this problem, we can use the equation:

x + y = 100 ounces

Where x = The number of ounces of strawberry juice

and y = The number of ounces of water

Since we know that Molly uses four times as many ounces of water for each ounce of strawberry juice, we can conclude that:

y = 4x

With this information, we can use substitution to solve for x.

x + y = 100 ounces

x + (4x) = 100

Combine like-terms.

5x = 100

x = 20

Now that we know the value of x, we can figure out how many ounces of strawberry juice and how many ounces of water Molly needs.

Since x = The number of ounces of strawberry juice, Molly needs to use 20 ounces of strawberry juice.

Since y = The number of ounces of water, Molly needs to use 80 ounces of strawberry juice. (y = 4x | x = 20 | y = 4(20) | y = 80)

~Hope this helps!~

7 0

2 years ago

suppose a spherical snowball with a diameter of 6 centimeters is melted in a large bowl. the resulting water is then poured into

scoray [572]

Oooh fun!

Alright,

formula for a sphere is (4 $\pi$ r^3)3
4*pi*6^3=2714.34/3
904.78

Now you can do this 2 ways. First is that a cone is 1/3 of a sphere with the same radius so just take 904.78 and multiply it by 1/3 and then by 2 to get 2/3 of it or do this.

cone~ (6^2*pi*10)/3
376.99

and subtract

<span>904.78-376.99=527.79
</span>
<span>527.79^3 greater. Check my math. I could be wrong.</span>

5 0

2 years ago

Read 2 more answers