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Soloha48 [4]
3 years ago
9

Bl Write a word equation for the combustion of sulfur.

Chemistry
1 answer:
PolarNik [594]3 years ago
4 0

 Example, when sulfur is burned in the air (one of my favorite chemical reactions) it combines with oxygen in the air to form an oxide. We consider this reaction in the form of a chemical equation: S (sulfur) + O2 (oxygen) |> SO2 (sulfur dioxide)

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The IE1, for iodine, is 1009 kJ/mol. Calculate the wavelength (in nm) of electromagnetic energy need to ionize an iodine atom. 1
egoroff_w [7]

Answer:

118.6nm

Explanation:

It is possible to calculate wavelength of any energetic process (As an ionization) using:

E = hc / λ <em>(1)</em>

<em>Where E is Energy, h is Planck constant (6.626x10⁻³⁴Js), c speed of light (3x10⁸ms⁻¹) and λ is wavelength In meters.</em>

As the energy to ionize 1 mole of iodine is 1009kJ, one atom requires:

(1009kJ / mol) ₓ (1mol / 6.022x10²³ atoms) = <em>1.6755x10⁻²¹kJ / atom</em>. = 1.6755x10⁻¹⁸J

Replacing in (1):

λ = hc / E

λ = 6.626x10⁻³⁴Js*3x10⁸ms⁻¹ / 1.6755x10⁻¹⁸J

λ = 1.186x10⁻⁷m

As 1m = 1x10⁹nm:

1.186x10⁻⁷m ₓ (1x10⁹nm / 1m) =

<h3>118.6nm</h3>
4 0
3 years ago
2Fe(s) + O2(g) → 2FeO(s)<br><br><br> To which category does this reaction belong?
Varvara68 [4.7K]

Answer:

Redox reactions

Explanation:

Redox reactions consists of both oxidation and reduction

one species gets oxidised and other species become reduced, both oxidation and reduction happen simultaneously

reduction is either gain of electrons or gain of hydrogen. in reduction the oxidation number of species reduces

in this reaction the reduction half equation is

O₂ + 4e --> 2O²⁻

oxidation is either loss of electrons or gain of oxygen. in oxidation the oxidation number of species increases.

Fe --> Fe²⁺ + 2e

since both these half reactions happen overall its a redox reaction

6 0
3 years ago
how many grams of water can be produced the combination of 10 grams of oxygen and 8 grams of hydrogen
Nikitich [7]

Answer:

Mass =  11.16 g

Explanation:

Given data:

Mass of hydrogen = 8 g

Mass of oxygen = 10 g

Mass of water produced = ?

Solution:

Chemical equation:

2H₂ + O₂         →      2H₂O

Number of moles of hydrogen:

Number of moles = mass / molar mass

Number of moles = 8 g/ 2 g/mol

Number of moles = 4 mol

Number of moles of oxygen:

Number of moles = mass / molar mass

Number of moles = 10 g/ 32 g/mol

Number of moles = 0.31 mol

now we will compare the moles of hydrogen and oxygen with water.

                   O₂          :           H₂O

                    1            :             2

                  0.31         :            2/1×0.31 = 0.62

                  H₂           :            H₂O

                    2            :              2

                     4            :              4

Number of moles of water formed by oxygen are less this it will act as limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 0.62 mol × 18 g/mol

Mass =  11.16 g

4 0
3 years ago
The mass per unit volume is substance is called
gregori [183]

The mass per volume of a substance is called its density.

8 0
4 years ago
Read 2 more answers
How many electrons could have the following set of quantum numbers?.
aleksley [76]

Answer:

2

Explanation:

As only 2 electrons can present in an orbital, so only 2 electrons in an atom can have this set of quantum numbers.

8 0
3 years ago
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