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Nikitich [7]
3 years ago
7

Which step will decrease the pressure of a gas inside a closed cubical container

Chemistry
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0
In order to <span>decrease the pressure of a gas inside a closed cubical container, you need to decrease the temperature of the container. The volume of the system is rigid so it means volume is constant. By the ideal gas law, temperature and pressure are directly related. Increasing the temperature, increases the pressure and the opposite to happens.</span>
amm18123 years ago
6 0

Answer:

It's D (decrease temperature)

Explanation:

Just took it on e2020

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Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu
oksano4ka [1.4K]

Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, K=\frac{[B]}{[A]}>1

As, both 5000 and 8\times 10^{7} are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

4 0
3 years ago
How many moles are 4.20 * 10 ^ 25 atoms of Ca?
aleksandr82 [10.1K]

Answer:

~69.744 moles of Ca

Explanation:

Using Avogadro's constant , we know that:

1 mole = 6.022 x 10^23 atoms

S0, the number of moles in 4.20 x 10^25 atoms of Ca:

=(4.20 x 10^25 x 1 )/(6.022 x 10^23)

~69.744 moles of Ca

Q2:How many atoms are in 0.35 moles of oxygen?

1 mole = 6.022 x 10^23 atoms

S0, the number of atoms in 0.35 moles of  oxygen:

=[0.35 x (6.022 x 10^23)]

=2.1077 x 10^23 atoms of Oxygen

Hope it helps:)

4 0
3 years ago
Which of the following is the si unit of acceleration
iris [78.8K]

Yo sup??

The answer to this question is option C ie

m/s^2

because the SI unit of distance is m and the SI unit of time is sec

Hope this helps

8 0
3 years ago
Read 2 more answers
Notice that the effective analytical connection for analysis of hypochlorite anion by the thiosulfate anion in this experiment i
hoa [83]

Answer:

b. Two moles of thiosulfate anion needed to react with one mole of hypochlorite anion.

Explanation:

1. Hypochlorite with iodide

                      2I⁻ ⟶ I₂ + 2e⁻

<u>ClO⁻ + 2H⁺ + 2e⁻ ⟶ Cl⁻ + H₂O      </u>

2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + H₂O

2. Thiosulfate with iodine

     2S₂O₃²⁻ ⟶ S₄O₆²⁻ + 2e⁻

<u>       I₂ + 2e⁻ ⟶ 2I⁻               </u>    

2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻

3. Sum of the reactions

                2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + H₂O

<u>                       2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻                    </u>

2I⁻ + ClO⁻ + 2S₂O₃²⁻ + 2H⁺ ⟶ I₂  + Cl⁻ + S₄O₆²⁻ + H₂O

4. Molar ratio

S₂O₃²⁻:ClO⁻ = 2:1

7 0
3 years ago
Two reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.79 2 C − ⇀ ↽ − D K 2 = 0.186 Calculate the
vfiekz [6]

Answer:

K=1.93

Explanation:

Given reactions are:

A +2B ⇄ 2C  K1=2.79

2C ⇄ D K2=0.186

D⇄ A+ 2B K=?

If we reverse the reaction then the euillibrium constant also become reciprocal of original value:

3rd reaction is a combination of reciprocal of 1st and 2nd reaction

2C⇄A +2B   1/K1;........................1

D ⇄ 2C  1/K2; ..............................2

On adding 1 and 2

D ⇄A +2B    K=\frac{1}{K1} \times\frac{1}{K2};

K=\frac{1}{2.79} \times\frac{1}{0.186};

K=1.93

4 0
3 years ago
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