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anygoal [31]
3 years ago
8

The mass per unit volume is substance is called

Chemistry
2 answers:
gregori [183]3 years ago
8 0

The mass per volume of a substance is called its density.

777dan777 [17]3 years ago
8 0

The mass per unit volume is substance called density.

Hope this helps

Have a great night

God bless you

- Kayla :)

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NeTakaya
It is achievable for the same enzyme to catalyze reverse reactions for the reason that the direction of a reversible reaction is determined by the concentrations of reactants and products. In pulmonary circulation, the low CO2 concentration supports the making of CO2 and H2O.
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3 years ago
How many moles of sodium carbonate are contained by 57.3g of sodium carbonate
Lady_Fox [76]

Answer:

\boxed {\boxed {\sf 0.541 \  mol \ Na_2CO_3}}

Explanation:

We are asked to find how many moles of sodium carbonate are in 57.3 grams of the substance.

Carbonate is CO₃ and has an oxidation number of -2. Sodium is Na and has an oxidation number of +1. There must be 2 moles of sodium so the charge of the sodium balances the charge of the carbonate. The formula is Na₂CO₃.

We will convert grams to moles using the molar mass or the mass of 1 mole of a substance. They are found on the Periodic Table as the atomic masses, but the units are grams per mole instead of atomic mass units. Look up the molar masses of the individual elements.

  • Na:  22.9897693 g/mol
  • C: 12.011 g/mol
  • O: 15.999 g/mol

Remember the formula contains subscripts. There are multiple moles of some elements in 1 mole of the compound. We multiply the element's molar mass by the subscript after it, then add everything together.

  • Na₂ = 22.9897693 * 2= 45.9795386 g/mol
  • O₃ = 15.999 * 3= 47.997 g/mol
  • Na₂CO₃= 45.9795386 + 12.011 + 47.997 =105.9875386 g/mol

We will convert using dimensional analysis. Set up a ratio using the molar mass.

\frac {105.9875386  \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}

We are converting 57.3 grams to moles, so we multiply by this value.

57.3 \ g \ Na_2CO_3} *\frac {105.9875386  \ g \ Na_2CO_3}{1 \ mol \ Na_2CO_3}

Flip the ratio so the units of grams of sodium carbonate cancel.

57.3 \ g \ Na_2CO_3} *\frac {1 \ mol \ Na_2CO_3}{105.9875386  \ g \ Na_2CO_3}

57.3 } *\frac {1 \ mol \ Na_2CO_3}{105.9875386 }

\frac {57.3 }{105.9875386 } \ mol \ Na_2CO_3

0.5406295944 \ mol \ Na_2CO_3

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place to the right tells us to round the 0 up to a 1.

0.541 \  mol \ Na_2CO_3

There are approximately <u>0.541 moles of sodium carbonate</u> in 57.3 grams.

6 0
2 years ago
Cual es la valencia del F CL Br I
bagirrra123 [75]

Answer: ok

Explanation: i known what your saying

3 0
3 years ago
I need help plez! Thank you!
vladimir2022 [97]
The answer should be E,C,F,B,A,D in that order.
6 0
3 years ago
Although not usually soluble in plain water, an amphoteric oxide or hydroxide is: 1. soluble in neutral solutions. 2. soluble in
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Answer:

The correct option is: 4. soluble in both acidic and basic solutions

Explanation:

Oxide is a chemical compound formed by an element with oxygen. In such compounds, the oxygen is generally present in the -2 oxidation state.

Whereas, hydroxide is a chemical compound formed by an element with hydroxyl group (-OH).

<em>Oxides and hydroxides of some elements are </em><em>amphoteric</em><em> in nature.</em> <u><em>Such compounds can behave as an acid in basic medium and behave as a base in acidic medium.</em></u>

<u>Therefore, amphoteric oxides and hydroxides are soluble in both acidic and basic solutions.</u>

5 0
3 years ago
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