Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Area of triangle = 1/2(4)(4) = 16/2 = 8
if Area of square then A = 4 x 4 = 16
so answer
B. it's one half the area of square of side length 4 units
Answer:
im sorry i dont understand
Step-by-step explanation:
Answer:
17 and x=constant,
4x=coefficient
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
5a^2
Step-by-step explanation:
5ax5a=5a^2