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3 years ago

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Convert 2.5 into Fraction and ¹⁹⁄₂₀ to decimal form

2 answers:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

0.25 would be 1/4 and 19/20 would be 0.95

Step-by-step explanation:

you can get 19/10 be divideing

and 0.25 by solving

Makovka662 [10]3 years ago

3 0

Let’s start with 2.5 into a fraction.

2.5 has a decimal and a whole number part, so you can know that you will have 2 as your whole number.

.5 is five tenths, so you could say 5/10.

5/10 simplified is 1/2.

2.5 as a fraction is 2 1/2.

19/20 is a little harder, but let’s start!

We need to find what 20 is multiplied by to get 100. 100 divided by 20 is 5.

Now that you have that number, you want to multiply both the numerator and the denominator by 5.

19 x 5 = 95
_____
20 x 5 = 100

95/100 is easy to turn into a decimal.

Ninety-five one hundredths is 95/100.

Ninety-five one hundredths is also .95

Your answers are 2 1/2 and .95

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What is the mean absolute deviation for 9, 7, 6, 8, 7, and 5? (2 points) a 1 b 2 c 6 d 7

Burka [1]

Answer: a. 1

Step-by-step explanation:

Given data: 9, 7, 6, 8, 7, and 5.

Mean absolute deviation: $MAD=\dfrac1n\sum^n_{i=1}|x_i-m|$ , where m = mean

mean (m) = $\frac{\text{Sum of values}}{\text{Number of values}}$

$=\frac{42}{6}\\\\=7$

Now, $MAD=\dfrac{|9-7|+|7-7|+|6-7|+|8-7|+|7-7|+|5-7|}{6}$

$MAD=\dfrac{2+0+1+1+0+2}{6}$

$MAD=\dfrac{6}{6}$

$MAD=1$

Hence, the mean absolute deviation=1

Thus correct option is a. 1

8 0

3 years ago

Joan wants to reduce the area of her posters by one-third. Draw lines to match the original dimensions in the left column with t

3241004551 [841]

Answer:

1) $30\ in\ by\ 12\ in$ --------> $120\ in^{2}$

2) $30\ in\ by\ 18\ in$ --------> $180\ in^{2}$

3) $12\ in\ by\ 15\ in$ --------> $60\ in^{2}$

4) $18\ in\ by\ 15\ in$ --------> $90\ in^{2}$

Step-by-step explanation:

<u>Verify each case</u>

case 1) $30\ in\ by\ 12\ in$

<em>Find the area with the original dimensions</em>

$A=30(12)=360\ in^{2}$

Reduce the area of the poster by one-third

$360/3=120\ in^{2}$

therefore

$30\ in\ by\ 12\ in$ --------> $120\ in^{2}$

case 2) $30\ in\ by\ 18\ in$

<em>Find the area with the original dimensions</em>

$A=30(18)=540\ in^{2}$

Reduce the area of the poster by one-third

$540/3=180\ in^{2}$

therefore

$30\ in\ by\ 18\ in$ --------> $180\ in^{2}$

case 3) $12\ in\ by\ 15\ in$

<em>Find the area with the original dimensions</em>

$A=12(15)=180\ in^{2}$

Reduce the area of the poster by one-third

$180/3=60\ in^{2}$

therefore

$12\ in\ by\ 15\ in$ --------> $60\ in^{2}$

case 4) $18\ in\ by\ 15\ in$

<em>Find the area with the original dimensions</em>

$A=18(15)=270\ in^{2}$

Reduce the area of the poster by one-third

$270/3=90\ in^{2}$

therefore

$18\ in\ by\ 15\ in$ --------> $90\ in^{2}$

6 0

4 years ago

How do you turn -7x+3y=15 into slope intercept form

Nutka1998 [239]

Rearrange it to its 3y= 7x+15. Then divide both sides by 3 to get y=7/3x+5

5 0

4 years ago

A triangle having sides of 2, 2, and 3 contains _____.

nikdorinn [45]

Don't quote me but i'm pretty sure it is a right triangle

8 0

4 years ago

Read 2 more answers

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 63 N acts on

Luba_88 [7]

Answer:

18 N

Step-by-step explanation:

Let <em>F</em> denote the force, <em>m</em> denote the mass of the object and <em>a </em>denote the acceleration of the object.

<em /> $F=ma$ <em />

$m = \frac{F_{1} }{a_{1} }=\frac{63}{7} =9 kg$

$F_{2} =ma_{2}=9*2=18N$

6 0

3 years ago