Find the dimensions of a rectangle whose perimeter is 18 meters and whose area is 20 square meters.

1 answer:

8 0

Call the length L and there width W. then perimeter is 2L+2W=18. area is LW=20.

2L+2W=18
L+W=9
LW=20
L=9-W
(9-W)W=20
W²-9W+20=0
(W-5)(W-4)=0
W=4,5

rectangle is 4by5

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$\text{Hey there!}$

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