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IRISSAK [1]
3 years ago
11

According to the following chemical

Chemistry
1 answer:
NeX [460]3 years ago
3 0
2 moles of SiO2 and 1 mole of C
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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a
FrozenT [24]

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

C (mg/m3) =(P/RT)*MW*C_{ppm}

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178

(b) For 200°C and 1.1 atm,

P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277

Then the concentration in mg/m3 is

C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625

5 0
3 years ago
Is be2+ stable or not?<br> is Ne stable or not?<br> is Br- stable or not?<br> is h+ stable or not?
amid [387]

Explanation:

be2+ stable

Ne stable

Br- stable

h+ notstable

3 0
4 years ago
Read 2 more answers
The volume density of atoms for a bcc lattice is 5 x 1026 m-3. Assume that the atoms are hard spheres with each atom touching it
ollegr [7]

Explanation:

It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.

This means that volume occupied by 2 atoms is equal to volume of the unit cell.

So, according to the volume density

        5 \times 10^{26} atoms = 1 [tex]m^{3}

        2 atoms = \frac{1 m^{3}}{5 \times 10^{26} atoms} \times 2 atoms

                     = 4 \times 10^{-27} m^{3}

Formula for volume of a cube is a^{3}. Therefore,

           Volume of the cube = 4 \times 10^{-27} m^{3}

As lattice constant (a) = (4 \times 10^{-27} m^{3})^{\frac{1}{3}}

                                   = 1.59 \times 10^{-9} m

Therefore, the value of lattice constant is 1.59 \times 10^{-9} m.

And, for bcc unit cell the value of radius is as follows.

                 r = \frac{\sqrt{3}}{4}a

Hence, effective radius of the atom is calculated as follows.

                 r = \frac{\sqrt{3}}{4}a

                   = \frac{\sqrt{3}}{4} \times 1.59 \times 10^{-9} m

                   = 6.9 \times 10^{-10} m

Hence, the value of effective radius of the atom is 6.9 \times 10^{-10} m.

3 0
3 years ago
Which statement is true about the products of two reactants that combine chemically?
Art [367]
I think its C i don't know if i am right
7 0
3 years ago
What does the symbol Pt mean in a chemical equation in chemistry?
uysha [10]

Explanation:

It is mean Platinum .

hope to helped.

5 0
4 years ago
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