Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is
Explanation:
It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.
This means that volume occupied by 2 atoms is equal to volume of the unit cell.
So, according to the volume density
2 atoms =
=
Formula for volume of a cube is . Therefore,
Volume of the cube =
As lattice constant (a) =
=
Therefore, the value of lattice constant is .
And, for bcc unit cell the value of radius is as follows.
r =
Hence, effective radius of the atom is calculated as follows.
r =
=
=
Hence, the value of effective radius of the atom is .