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Alekssandra [29.7K]
2 years ago
8

Which of the following steps correctly converts 3 moles of fluorine to an equivalent number of particles of fluorine? Divide Avo

gadro's number by 3. Multiply 3 by Avogadro's number. Divide the atomic mass of fluorine by 3. Multiply 3 by the atomic mass of fluorine.
Chemistry
1 answer:
Eva8 [605]2 years ago
8 0

Answer:

Multiply 3 by Avogadro's number.

Explanation:

The mole can be defined as the amount of a substance that contains Avogadro’s number of particles, 6.02 x 10²³.

For elementary particles:

Number of particles=

number of moles x 6.02 x10²³

From the question,

Number of moles = 3moles

Number of particles = 3 x 6.02 x10²³

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Complete the acid–base equation for the dissolution of the following compound into liquid HF solvent. The relevant pKa values ar
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Answer:

The balanced chemical equation: NH₃ + 2 HF → NH₄⁺ + HF₂⁻

Explanation:

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In this reaction, a Brønsted–Lowry acid loses a proton to form a conjugate base. Whereas, a Brønsted–Lowry base accepts a proton to form a conjugate acid.

Acid + Base ⇌ Conjugate Base + Conjugate Acid

The acid dissociation constant (Kₐ) <em>signifies the acidic strength of a chemical species.</em>

∵ pKₐ = - log Kₐ

Thus for a strong acid, Kₐ value is large and pKₐ value is small.

pKₐ (HF) = 3.2 → strong acid

pKₐ (NH₃) = 38 → weak acid

<u>The chemical reaction involved in the dissolution process:</u>

NH₃ + 2 HF → NH₄⁺ + HF₂⁻

In this acid-base reaction, the acid HF reacts with NH₃ base to give the conjugate base HF₂⁻ and conjugate acid NH₄⁺.

<u>HF (acid) donates a proton to form the conjugate base, HF₂⁻ ion. NH₃ (base) accepts a proton to form the conjugate acid. </u>

7 0
3 years ago
Hurry PLEASE HELP!
avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Nt=25 g

No=100 g

t1/2=5770 years

\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years

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