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Alekssandra [29.7K]
3 years ago
8

Which of the following steps correctly converts 3 moles of fluorine to an equivalent number of particles of fluorine? Divide Avo

gadro's number by 3. Multiply 3 by Avogadro's number. Divide the atomic mass of fluorine by 3. Multiply 3 by the atomic mass of fluorine.
Chemistry
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

Multiply 3 by Avogadro's number.

Explanation:

The mole can be defined as the amount of a substance that contains Avogadro’s number of particles, 6.02 x 10²³.

For elementary particles:

Number of particles=

number of moles x 6.02 x10²³

From the question,

Number of moles = 3moles

Number of particles = 3 x 6.02 x10²³

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Below is a generic equation for a reaction. If I mix 2 units of A, with 6 units of B, which of the following is true?2A + 3B ? C
Allisa [31]

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E. Substance A will be the limiting reactant.

Explanation:

Below is a generic equation for a reaction.

2A + 3B → C + 3DA

According to the balanced equation, the theoretical molar ratio of A to B is 2:3, that is, 2 moles of A react with 3 moles of B.

<em>If I mix 2 units of A, with 6 units of B, which of the following is true?</em>

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<em>B. Both reactants will fully react.</em> FALSE.

<em>C. Not enough information given.</em> FALSE.

<em>D. Substance B will be the limiting reactant.</em> FALSE. Substance B will be the reactant in excess because there are 6 moles and only 3 moles are required.

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7 0
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Read 2 more answers
The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23
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Answer:  The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)

\Delta H^0=232KJ

Now we have to determine the value of \Delta H for the following reaction i.e,

)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g) \Delta H^0'=?

According to the Hess’s law, if we reverse the reaction then the \Delta H will change its sign and if we half the reaction, then the

So, the value \Delta H^0' for the reaction will be:

\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ

Hence, the standard enthalpy change for this reaction is -116 kJ

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4 years ago
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