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kvasek [131]
3 years ago
12

1. classify the triangle by its sides

Mathematics
1 answer:
torisob [31]3 years ago
6 0
The first one is isosceles because it has two side lengths that are the same, C.
The missing angle measure is 35° because all of them together should add up to 180° and 105+40+35=180, A.
The possible lengths for the third triangle e are in between 7, and 17. This is because the possible side lengths are in between adding the two side lengths together, (12+5=17) and subtracting the littler side by the bigger side. (12-5=7)

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10pts dont answer bogus or reported
ELEN [110]

Answer:

6 hours and 45 minutes

Step-by-step explanation:

162÷24=6.75

6.75=6 hours and 45 min

4 0
3 years ago
Y=(6+3X)^2/3 Find the derivative of the function using the chain rule
fomenos
\bf y=(6+3x)^{\frac{2}{3}}\implies \cfrac{dy}{dx}=\stackrel{chain~rule}{\cfrac{2}{3}(6+3x)^{\frac{2}{3}-1}\cdot (0+3)}
\\\\\\
\cfrac{dy}{dx}=\cfrac{2}{3}(6+3x)^{-\frac{1}{3}}\cdot 3\implies \cfrac{dy}{dx}=2(6+3x)^{-\frac{1}{3}}\implies \cfrac{dy}{dx}=\cfrac{2}{\sqrt[3]{6+3x}}
5 0
4 years ago
35% of the original price of a phone is £78 what was the original price ?
Yakvenalex [24]

Answer:

222.86

Step-by-step explanation:

<h2><u>in order to solve this question you can create an equation :</u></h2>

35% * x = 78

where x is the original amount

in order to get x , you have to say :

78/ 35% = x

hence x = 222.8571...

to 2dp = 222.86

4 0
3 years ago
Read 2 more answers
Perimeter of a triangle with side lengths 2x, (3x-1) and (4x+5)?
frez [133]

Does is have a total perimeter of the triangle? If not, the closest you can get is by simplifying.

2x+3x-1+4x+5

9x+4

6 0
3 years ago
37% dextrose solution (37 mg per 100ml of solution) is given iv. Suppose a total of 3.81 liters is given over a 15 hour period.
sashaice [31]

Answer:

During 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be 93.98 mg/hour.

Step-by-step explanation:

If a total of 3.81 liters of the solution is given over a 15 hour period.

Now, 1 liter is equivalent to 1000 ml

So, a total of 3810 ml of the solution is given over a 15 hour period.

If 100 ml of solution contains 37 mg of dextrose, then 3810 ml of the solution will contain \frac{37 \times 3810}{100} = 1409.7 mg of dextrose.

So, during the 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be \frac{1409.7}{15} = 93.98 mg/hour. (Answer)

7 0
3 years ago
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